Linear piston ratchet engine, 99% efficiency. Proto type in action!

[Tommey Reed]

This is another engine design called the ratchet engine.
at 120 psi and a 12" stroke for each piston, this design converts linear into rotational energy.

At 12" stroke the formula for conversion is (24" x pi)/12)=6.28 ft and 120/12=10ft/lb for each revolution.
6.28 x 10 = 62.8 lb for each revolution of crank shaft for each 12cu/in of air.
At 600 rpm's this will produce (62.8 x 600)/33000= 1.14 hp
The amount of cfm's is (12x600)/1728 = 4.17 at 120 psi......


Proto-type in action.

http://www.youtube.com/user/OverUnityNow1#play/all/uploads-all/0/ccic7CH4sOY

Tom...

[AlanA]

Hello Tommey,

I have seen you video and I have seen other videos about the ratchet engine which are no more available at youtube.
However I think that the ratchet engine is very powerful. In opposite to the Reciprocating engine the ratchen engine has no upper dead point and the lower dead point. The ratchet engine is powerful in every inch of its movement (ft lbs). Sadly the ratchet engine hasn't very much HPs. Is it possible to construct a larger engine with more HPs?

Could you please explain the formulas:
The stroke is 12 why is the figure 24" in the formule (24" x pi)/12). What means the 12 in the formula?
You have also written down this formula: (62.8 x 600)/33000. What means the 33000.
And also the formula for the cfms is not clear to me: (12x600)/1728. What means the 1728.

Please be patient with me. I am not so fit in maths als you.

Alana

[Tommey Reed]

The Ratchet engine is calculated using many formulas.

We must first look at the piston size in cubic inches.

Lets start with say 2" diameter piston, the total is (3.14x(r^2))=3.14cu/in total piston area.

If we use a 4" gear on the output shaft, we can calculate how long the rack gear needs to be for 1 revolution per stroke:
the circumference of the 4" gear is (pi x d) or 3.14 x 4 =12.56in per stroke for each revolution of shaft.
Now we have all the formulas to calculation torque:

At 100 psi on the piston with a area of 3.14cu/in we have 100 x 3.14=314 psi

having a 4" gear or 4"/2= 2" then we can take 314 psi x 2"= 628 psi or 628/12=52.33 foot pounds

At 12.56 piston stroke the will turn the shaft one full revolution at 6.28ft distant for each stroke the total output is 328.65 lb of work
At say 500 rpms we can calculate total work in one minute:
(500 x 328.65)/33000 =4.98hp
Or
(52.33ft/lb x 500rpm's)/5252=4.98hp

you can also calculate CFM's too:
3.14cu/in x 12.56" stroke =39.44 cu/in for each stroke
39.44cu/in x 500 rpm's =19719.2 cu/in in one minute

19719.2/1728=11.41 CFM's per minute that will produce 4.98hp at 100 psi of constant air pressure.....

I hope this helps you understand the true power of the Ratchet Engine...

Tom :-)

[AlanA]

Thanks for the calculations. They clarify my questions.
Have you ever thought to reuse the air?
The ratchet engine is very powerful but isn't it a loss of energy to use the air only once?

Alana

[Tommey Reed]

Any time you try to reuse air, its like puting a load on any system.
In other words, if I try to get 10 psi out of the air engine, I will also take 10psi from the intake pressure.
But, if I use lower pressure say 40 psi, then the compressors will be able to keep up with the CFM's.

Also if i use 300 psi at 1cu/in and inject it to to the engine, the expand air will still be able to finish with the piston moving 12.56 in. This will have 23 psi left over...

Tom...