Prof. Tutor shows Zero Point energy extraction into mechanical rotation

[hartiberlin]

Have a look at some great research breakthrough
in converting ZPE into mechanical rotation:

http://www.youtube.com/watch?v=IiC2IGLl90Q

Author: Prof. Dr. Claus W. Turtur University of Applied Sciences Braunschweig - Wolfenbüttel, GERMANY

Here are his scientific papers about it.

http://www.ostfalia.de/cms/de/pws/turtur/FundE/English/

Well done.

Now this only needs to be scaled up and run by charged capacitors
or big  Electrets.
Regards, Stefan.

[spoondini]

I also found this fascinating.  I made a rotor from foil and was able to get rotation with a balloon, as indicated in his paper.

Thread below had quite a bit of discussion on this topic.

http://www.overunity.com/index.php?topic=7723.msg189404#msg189404

[fabver]

Hi @all,

probably with 10KV it's easy make a elettrostatic motor , but the COP is not > 1.

[jibbguy]

Regarding it being an electrostatic motor: Not correct. There is no electrostatic or electromagnetic electrical current flow in this device. Voltage is only the bias that allows ZPE to be utilized. This is proved by his earlier Papers where it ran the same, or even better, when in a vacuum.

Regarding it not being OU: Not necessarily always true (although Dr. Turtur's present design in the vid would appear to not be "OU").

The device is not "using" current from the supply: Only the Voltage Potential.... Meaning what ever losses that exist, are dependent on the power supply's design and efficiency. Even with a "no load" situation (as this is), it will waste some watts just operating through filter cap leakage, RC resistors, stray R, step-up transformer losses, etc.

What kinds of very simple "power supplies" do we know of that can generate several tens of K-V of long-lasting Potential with very little work needed.... But provide only milli-watts of actual power?

Since there is no actual current flow, the "watts" are not important here, only the "Volts". A Whimhurst, or even hair and a toy balloon should do it (if the atmosphere is dry enough).

Lol, or a kite and a key

Hmm. Makes you wonder about other stuff: Like why certain semiconductors are so sensitive to static electricity... Could the static potential be triggering a "spike" of ZPE coming from the aether, manifesting itself as EM or ES energy and then burning the device out? Prolly not lol, but fun to think about

[fritz]

A turning dielectric without perfect symmetry in an electrostatic fields connected to a voltage source will have an oscillating capacity and an oscillating charge - and there will be of course an oscillating current.
If we assume that there are pretty no perfect HV voltage sources - and that the response of the HV voltage source regulation circuit is not infinite fast - this regulation circuit might be responsilble for re-gauge.
Operating that thing from a charged cap would give immediate proof of concept.

If the thing turns from a state of higher capacity to a lower capacity state - it releases charge  to the supply - acts as source. If it turns from lower capacity state to higher capacity state - it draws current from the supply.

If u assume that the output impedance of the supply changes with output voltage (whats for sure) -  you can assume that 10kv is the threshold where the electrostatic force which keeps the thing on track against the water (the thing is frozen in its electrical minimum - but not balanced from swimming point of view) is exceeded.

So without proper current/voltage measurements _ or operation from a charged cap _ this is just another funny half-mechanical HV oscillator - powered from the negative resistance of the HV supply - which finally gets his power from mains.

(And we havent talked about the voltage supply internal losses yet)

The oscillation energy is transfered between the misbalanced wheel(potential energy) - and the charge.
If the output resistance of the voltage supply increases >=10kv - the mechnical potential energy stored is transfered into mechanical inertia. The resulting turn releases charge to the supply - means a negative current which results in a down regulating response of the HV voltage source - which adds an additional pull. If the wheel reaches the point of minimum capacity (all delta charge released) the current to the supply changes from minus to zero and the regulation circuit has to backup with a positive pulse to maintain the output voltage. If the involved time-constants fit - this pulse (which can also be seen as time interval with low output impedance) can be enough to move the wheel back to the state of maximum potential energy) - we have a perfect motor;-))