THE OVERUNITY RING

[innovation_station]

NO BUT YOU CAN LOOK AT THE SPECKS FOR THE CAPS FROM THE MAKER OF THEM ..

MAXWELL

RATEINGS ON 1 OF THEASE CAPS ..... AS FOLLOWS

1SEC MAX CURRENT PEEK 875 A

CONTINOUS 105 A

SHORT CURCUIT 3500 AMPS...... HUMMMMM

HERE IS THE LINK TO THE SITE READ UP ...  A FRIEND OF MINE SELLS THEM...  CHEEPEST YOULL FIND ON THE ENTIRE INTER NET ...  AND HE SAID THE DAY I RELEASED THIS IDEA...  THAT SOME ONE BOUGHT 190 000 OF THEM ... SO THERE AINT MANY LEFT!

http://www.maxwell.com/ultracapacitors/products/large-cell/bcap0650.asp

SO YOULL EATHER BUILD IT FRONT LINES ... OR LURK IN THE SHADOWES .... EATHER WAY ... IT GETS BUILT! 

[MrMag]

It's just too bad that you don't understand what I am trying to tell you.
Good luck

[innovation_station]

I THINK YOU THINK I AM GOING TO RUN THIS FULL STEAM THIS IS NOT THE CASE THIS DEVICE OPERATES ON TIME ...

AND YES ENGERY ENTERS THIS SYSTEM FROM A SEAMLY FREE SOURCE ... NOT THE CASE ...

OUTPUT IS MORE THAN INPUT ...

BUT YOU CAN SEE THAT BY DESIGN ...   SURELY ..

I THINK MANY FAIL TO SEE WHAT I HAVE ACHIEVED ... I HAVE NO WORRIES AND IM FULLY CONFIDENT I CAN BUILD THIS UNIT WITH EASE ...

THIS IS NOT MY GOAL MY QUESTION IS CAN YOU BUILD THIS ... IF YOUR ANSWER IS NO I HAVE FAILED AT MY JOB ....

THANK YOU ...

WILLIAM

[EMdevices]

IST and Mr.Mag,  both of you, take a deep breath....

Ok,  somebody needed to set you straight IST and apparently MrMag failed too.

First off,  Capacitors don't store POWER, but energy.  The rating on the BCAP3000  is 3000 Farads.   The max voltage allowed is 2.7 Volts.  So if you were to charge one of these capacitors to 2.7 volts,  your energy stored in the full capacitor is:

U_cap = 0.5 * C * V^2 = 0.5 x 3000 x (2.7)^2 = 10935 Joules.

Now one of my AA NiMH batteries has a rating of 2500 mAhours, which means the equivalent energy in the battery is:

U_aa = (2.5 A)*(1.3 V) * (3600 sec) = 11700 Joules

Pretty close ey,  you see it's comparable energy but obviously the capacitor is a lot bigger in volume.

So why choose one over the other? 

Well it's all about the internal resistance.  If you have a high internal resistance and draw a lot of current you will have huge losses and heating problems  (I^2 * R losses), so they made these capacitors to have a very low internal resistance, check out those crazy values,  0.29 mOHMS.   You can discharge them quickly as compared to a battery which has a much much higher internal resistance.

EM

P.S.  IST, be very careful.  If you attempt to deform cans or shrink coins using these capacitors, and they will work wonderfully (just use a high amperage SCR to trigger), then be aware that wire can explode under that kind of instantaneous current and the shrapnel can wound you pretty badly.  Always wear eye protection and stay away from the experiment plus use shielding, etc..  use common sense man, I hate to see you get hurt.

P.S.  Can your friend give me a deal on some of these capacitors?  I wouldn't mind buying a few.  I can use them in an electric vehicle to provide strong acceleration, something you just can't do with only batteries, for the same reasons explained above.

[forest]

I'm now convinced that it's all about how fast we can charge and discharge capacitors. No need to use gigantic ones, just energy of 1W to 30W stored in capacitor(s) is enough if we could discharge it a the rate say 2000 times per second. Did you all forgot excellent "The Tesla project" thread !?

What I want to know is how to compute energy stored in coil for a given period of time  of short-circuit it with power source. I know it depends on inductance,resistance,duration of short-circuit,amperage and voltage of power source. Can you give me the right direction and equations ?

MrMag - here is a real power at high frequency high voltage and high amperage (at the output stage) - The Tesla method of conversion which is two oscillators and make&break between them.
The key is what Tesla discovered but what we don't appreciate - we can have most of the time a lot of currents flowing in the same circuit ,depended only on relative power source.We CAN discharge capacitor into one coil while charging second coil from short-circuit to the power source.Then discharge coil into capacitor immediately because it's a nature of coil "kick" - to flow very fast.Do it alternately and you can make capacitor discharge at any rate desired.Of course synchronization is needed between charging and discharging. All we need to know is how to made correct high self-inductance coil to store enough energy during half of period of oscillation.it has to be optimal to not drain battery and still store enough energy.

Did I mentioned that we could put a few such stages in series (while discharging one capacitor ,charging the second) or in parallel (charging one oscillator stage from the previous).
The missing is now only the output stage. We have a swing already made.

Just please help with equations so we can work without guessing