Second Stage Joule Thief Circuits

[PaulLowrance]

Cool, some details. Thanks for the exp. data Yucca. It sounds like gadget & the gang believe the key is in *large* caps & batteries. Maybe 1F is not enough. Correct me if I'm wrong, but for ages bedini has said the secret is in the battery, more specifically *large* batteries, no?

Paul

[innovation_station]

sure it is ... 

because he ringgggs the battery .... 

useing the kick

ist!

shake the electrons out of the material ... 

you see key to this is to keep it MAGNETIC IN THE CORE ... THEN I CAN PUT 500 TUNED OUTPUT COILS ... 0 LOSS!! 

we awake yet ... 

[jadaro2600]

IST< I swear, if you exploded one day, confetti would fly everywhere, and surely we would see all-over-unity!

jadaro2600,

Voltage is not an accurate way of determining battery energy-- Key word is "accurate."  For example it's inaccurate to judge how fast an object is moving by human sight alone, but I'll bet you anything I can tell which bowling ball is dropping faster between one that was dropped 5 feet & 100 feet. Here is gadgets claim, which is very obvious,

And I would add that he was talking about the 650F ultracap, right gadget?

Paul

I mean to be constructive to the cause:

I'm not sure I follow you Paul; What I'm asking is How do you know how full a capacitor is - voltage alone is not sufficient to determine this, I could charge a 12v capacitor to 3v, would it be 1/4th full?  Please explain!

For what its worth poynt, I don't see that you've bashed anyone either, you've just been calm and objective as usual.

Last night I replicated the gadget circuit using a constant V source of 1.5V to drive it through a 1ohm non inductive resistor. The charging cap on the OP was a 1F 5V supercap.

[1]
I scoped the input V and I and used my scope to multiply the channels and then perform RMS, thus calculating AVG power in. I timed the run and multiplied power by seconds hence calculating input Joules.

[2]
I measured the start and finish V in the OP cap. Hence calculating output joules. (I was assuming the cap really was 1F)

With tweaking of the base pot I was able to achieve nearly COP 80%.

Perhaps there is something very special about these 650F caps?

Most of these high end capacitor are electrolytic, and act like a fast charging battery.


Gadget, please examine the following pictures and tell me that you're not using a battery?, and instead using a fully charged capacitor as the source?, one say, that you haven't assumed has been fully charged by the joule thief circuit, and instead from a steady independent source?: for instance...use a battery to charge the capacitor, and the insert it into the circuit.

>if what you're saying is true, then persistently changing the source from one to another would eventually cause the voltage on the right (in the charged capacitor) to climb.
>if you not disconnecting the source, then the path will short from positive to negative and, yes, the wire/heater element will get hot when you turn the switch on.
>if you're are disconnecting the source, then flipping the switch, the capacitor will discharge through the heater/wire, but still, the capacitor will have been be charged via the short from the source (battery or capacitor on the left )(+) to ground through the diode into the capacitor on the right.

What you essentially have is a battery on both sides of the oscillator circuit even if one or both of those are capacitors.

In this configuration, the oscillator only serves to boost voltage, barring the math, it is as if you've connected one charge capacitor in parallel with one discharged capacitor. Logically, ignoring the decay of charge associated with leakage, the charge in the full capacitor will become one half what it was and the discharged capacitor will gain one half it's full charge.

What theoretically happens is that the stored capacity on the left at some point in time is cut in half, and at some point in time, the stored capacity on the right is at one half yet the voltage is higher ( due to the oscillator ).

Over unity would occur is if the stored capacity on the right is one half BEFORE the stored capacity on the left is one half - which will not likely be the case because of the oscillator having a path to ground, thus it is discharging current.

[PaulLowrance]

It says 30$+9$ for shipping within US only, no other country can be chosen.

Broli, did you read the page. Scroll down 2.5  pages and it says,

For International Sales and Technical questions please email hlandis@hotmail.com

Paul

[innovation_station]

thanks j2600


so now you see how all of this ties right into teleportation ...

what is occouring in the battery ...

is how i seperate your spins ...

same deal!

w814

but it im sure is done boom  a 1 zap pulse ... and your just gone ... here there where ever  tic boom
tic boom

faster than light ...  the caps are filled faster than light ...  hence the gain of time tesla speeks of ..

you got to use hot to seperate cold  and cold to seperate hot ...

ac hot cold tho  not hot + 0 hot -   this is wrong ...   this fights nature   you must work with her