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Overunity Machines Forum



Second Stage Joule Thief Circuits

Started by Pirate88179, November 21, 2009, 02:06:51 PM

Previous topic - Next topic

0 Members and 4 Guests are viewing this topic.

gadgetmall

@jarado  It works as i posted . all the number . The problem is most of you DOn't have the New technology 650farad 2.7 volts BATTERY CAPACITOR > they are not related in any way to the old technology . take a full 2.7 volts @3500 amps (SPecs) and do the math fromthat . Also keep in mind what i have already said 5 times before you cannot charge this cap up with a 1.4 volts battery or for that fact you will smoke you 10 amp 12 volt battery charger trying to charge one up . I said i charge this cap up to full capacity from a 1.4 volt battery and the battery is still 1.4 after i charge it. if i go .r to the 100th and thousands scale then 1.495 AA battery 2500 ma  STart 1.495 battery end -cap fully charged at the rating 2.6 at 2500amps or just a fraction less  . Energy Stored including Jouled /watts amps are way Over the unity of the run battery volts and apm . you see?. and yes for the 15 th time i did three experimenst covering all the bases and now i am still doing an experiment giving you the time  battery volts and Bcap volts with a 7 year old cadinium china battery with less than 850ma rating when it was new . Volts are porportional to AMPS an Untra cap . Its a sort of solid state battery . way more powerfull than a single cell in a led acid car battery . powerfull and the power out put can be taken off SLOW for days weeks or i can discharge it like i do with Nichrome wire heater to a volts that i wanted to get to . 1 volt. Anyways . you all I can't answer anymore questions . I am on My way to radio Shack and get a few solder breadboards to build the self run circuit  l8r

"...Ultracapacitors have greater specific power (more than 1.5kW/kg) than conventional or advanced batteries; and higher specific energy (of about 3 to 5 Wh/kg) than aluminum electrolytic capacitors (Dietrich, 2001; Burke and Miller, 2002). Their advantage over batteries, in terms of power, is due to their reduced equivalent series resistance (ESR) and that in these elements, unlike batteries, there are no chemical reactions involved in the process of charge and discharge. Therefore, the speed needed to deliver energy does not depend on the speed of such reactions or the ability of chemical components to recombine, but on electrostatic phenomena, which does not require molecular mutation to take place. Also, the longer cycle life and good behavior at low temperatures (Schneuwly and Smith, 2005) are important advantages..."


Gadget
there you go again BUD.  Asking the same questions over and over and over  and Now Badgering me with you SEE this is what i liek to read BLA BLA BLA go play with you spice program and input the number and let do the math for you so wount have to lift a finger . I don't this you ever built a joule thief anyways . One more comment like that and your history .
Al
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PaulLowrance

Quote from: gadgetmall on November 23, 2009, 12:45:54 PMI said i charge this cap ["650farad 2.7 volts BATTERY CAPACITOR"] up to full capacity from a 1.4 volt battery and the battery is still 1.4 after i charge it

You see, those are the kind of statements I love to read! Because if you're correct, then I'd bet with anyone that it must be > cop 1 *unless* for obvious reasons there was something seriously wrong with your cap or voltage meter or what equipment used.

... looking forward to testing your claim.

Regards,
Paul

poynt99

Quote from: Yucca on November 23, 2009, 11:52:10 AM
For what its worth poynt, I don't see that you've bashed anyone either, you've just been calm and objective as usual.

Last night I replicated the gadget circuit using a constant V source of 1.5V to drive it through a 1ohm non inductive resistor. The charging cap on the OP was a 1F 5V supercap.

[1]
I scoped the input V and I and used my scope to multiply the channels and then perform RMS, thus calculating AVG power in. I timed the run and multiplied power by seconds hence calculating input Joules.

[2]
I measured the start and finish V in the OP cap. Hence calculating output joules. (I was assuming the cap really was 1F)

With tweaking of the base pot I was able to achieve nearly COP 80%.

Perhaps there is something very special about these 650F caps?

Thanks Yucca, much appreciated :)

Also appreciated is your test effort and clear, concise, and frank reporting of the results. More folks ought to aspire to this.

I've started a new JT thread here:
http://www.overunity.com/index.php?topic=8345.msg210413#msg210413

.99
question everything, double check the facts, THEN decide your path...

Simple Cheap Low Power Oscillators V2.0
http://www.overunity.com/index.php?action=downloads;sa=view;down=248
Towards Realizing the TPU V1.4: http://www.overunity.com/index.php?action=downloads;sa=view;down=217
Capacitor Energy Transfer Experiments V1.0: http://www.overunity.com/index.php?action=downloads;sa=view;down=209

PaulLowrance

Quote from: jadaro2600 on November 23, 2009, 12:23:06 PM
I'm not sure I follow you Paul; What I'm asking is How do you know how full a capacitor is - voltage alone is not sufficient to determine this, I could charge a 12v capacitor to 3v, would it be 1/4th full?  Please explain!
Most of these high end capacitor are electrolytic, and act like a fast charging battery.

I don't what you're talking about because in my reply to your statement I never said anything about how full a capacitor is. My reply to you was clearly about batteries. Which do you to talk about. Here's your quote,

QuoteVoltage isn't a great indication of power, in order to fully measure the power in watts, or coulombs, you would need a way to measure exactly how 'full' you capacitor really is.

In terms of conventional science, you can calculate the energy in a battery or capacitor. I've provided one example for 12V car batteries. As far as capacitors, I think everyone here knows the equations. If you want to know how full a capacitor is, then it would be the caps voltage rating.

Paul

PaulLowrance

I would like to say that there is nothing wrong with using a battery, supercap / ultracap in such test so long as the tester knows how to properly determine the amount of energy contained in it, which is not that difficult given control experiments.

Paul