Joule Thief 101

[EMJunkie]

Brad, this certianly kicks the wrinkles out of their pants!!!

Maybe Minnie and MilleHehehehe might stop and think, before "thinking" they know what they are talking about, aka: sticking their feet in their mouths?

   Chris Sykes
       hyiq.org

[MileHigh]

After that posting #1620, now we know we are not in Kansas anymore!  LOL and SMH

Chris, you have been fried by your own dots.

[EMJunkie]

After that posting #1620, now we know we are not in Kansas anymore!  LOL and SMH

Chris, you have been fried by your own dots.

Still a terrible case of foot in Mouth!!!

Your Drivel   vs   My Scientific Proof with References and everyday Provable Facts - No competition!!!

   Chris Sykes
       hyiq.org

[shylo]

When I use a coil for generating and motoring, since I have 2 magnet rotors and a set of coils in-between the 2, I use the flyback from motor shut-off (now it's generating),store it and use it to motor.
Chris's simple test of taking a coil ,shorting it , and then swiping a magnet across the surface of the coil , one feels the effects of Lenz.
Luc's latest is to me basically an electro-magnet?
I'm trying to get the fields to flip at just right time.
artv

[TinselKoala]

Certainly Brad, see below:




@TK - Although you did replicate Brads experiment, you got it wrong.

Faraday's law of induction is a basic law of electromagnetism predicting how a magnetic field will interact with an electric circuit to produce an Electromotive Force, E.M.F (e), is defined in Coulomb's of Charge (C), this is measured in Volts (V)

The Ampere (A), often shortened to "amp", is the SI unit of Electric Current (I), The ampere is equivalent to one coulomb (roughly 6.241×1018 times the elementary charge) per second. Amperes are used to express flow rate of electric charge.

Here in lies the problem. Brads Circuit is looking at Current (I) or Amperes on one side of the Circuit, and on the other, it is looking at the Voltage (V).

As you correctly pointed out:

So, you are comparing Apples and Oranges, this cant be done!!! This is wrong!!! EMF, when talking about EMF, must be compared with its couneter part, the Negative of the source EMF which IS and always will be, 180 Degrees out of phase!

Saying that 10 cars are out on the road, and 10 cars went down the road at 200MPH are totally different things, Volume vs Speed and one is not the other!

I am sorry TK but you are giving people a Bung Steer and this is very important!!!


So, E.M.F (e) has a phase relationship of 180 Degrees to the Source.


   Chris Sykes
       hyiq.org

Read your own post. EMF is _voltage_.  And as I have DEMONSTRATED, and as FARADAY's LAW STATES CLEARLY, the relationship between induced voltage and inducing magnetic field (current) is 90 degrees. When the time rate of change of the magnetic field (dB/dt) is maximum, the induced EMF is maximum. When the time rate of change of the magnetic field (dB/dt) is zero, the induced EMF is zero. You can clearly see this on the oscillograms. For you who have no calculus, the _slope_ of a voltage vs time graph is the time rate of change of the voltage. When the slope is horizontal (at the peaks) the instantaneous time rate of change -- the slope --is zero. When the sine wave crosses the zero axis, the slope is at its steepest, so the time rate of change (instantaneous) is at maximum, hence the induced voltage is maximum (and of opposite sign.) Faraday's Law in its simplest form: EMF (induced voltage) = - dB/dt. (instantaneous time rate of change of B).

The transformer diagram you keep posting is comparing CURRENT AND CURRENT. Brad's schematic and my testing compares CURRENT AND VOLTAGE. The secondary current in your transformer diagram does what all currents through an inductor do: it lags behind the applied voltage. The primary induces a VOLTAGE in the secondary that is 90 degrees out of phase of the primary CURRENT, as Faraday's Law clearly states. This induced voltage in the secondary then causes a CURRENT that is itself delayed due to the inductance of the secondary, adding up to an additional phase shift. If you have the frequency correct, this additional phase shift in the CURRENT can be 90 degrees IN ADDITION TO the 90 degrees shift in the INDUCED VOLTAGE a la Faraday's Law. So you can see a total 180 degree phase shift in the secondary CURRENT when compared to the primary CURRENT.

When you spin an ordinary PM generator at a certain RPM you get a certain voltage output. When you spin the generator _faster_ you get a _higher_ voltage output. Why? Because the _time rate of change_ of the magnetic fields linking the windings is increased. Faraday's law of induction again.