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[teslaalset]

Hi all 
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[exnihiloest]

This has already been clarified. Read for instance what @Omega_0 posted on the subject and try to understand it. This discussion is not in need of input by confused individuals.

All open and critical minds need such discussions, especially when under-qualified people pretend to hold the truth when they present only invasive rantings.

[Omnibus]

For the current, I think we should wait till I straighten out the power supply problem. The voltage measurement seems to be right. I'm measuring the 1Hz signal with my Keithley 2000, doubling the scope measurement, and it appears to reproduce what's on the scope screen.

[Omnibus]

All open and critical minds need such discussions, especially when under-qualified people pretend to hold the truth when they present only invasive rantings.

No, distractions and sidetracking such as aggressive misunderstanding of the role the active component of the impedance plays is detrimental to such discussions.

[LarryC]

Don't want to be a distractor or sidetracker, just want to show the facts from another test setup. My goal is not super accuracy, but just to show how this setup can produce correct results.

The first pic shows a stepdown transformer (120V to 6V) gone into a 1 Ohm resistor and a Radio Shack transformer with 51.1 Ohm primary. The resistor is wire wound, but the inductance is only 7 MH and would have insignificant inductive reaction. The transformer has an inductance of 1.413 H and has a huge induction reactance of 525 Ohms at 60 HZ. So this is a series RL circuit.

In the scope pictures the Vrms of the 1 Ohm resistor is shown in the middle column, second row. With a 1 Ohm resistor MV is equal to MA.

The first scope pic shows the voltage across the transformer primary(yellow Vrms = 6.55) and the voltage across the 1 Ohm resistor(blue Vrms = .00347) with the secondary open. Note the out of phase wave.

The second scope pic shows the voltage across the transformer primary (yellow Vrms = 6.44) and the voltage across the Ohm resistor (blue Vrms = .0533)  with the secondary using low resistance. Note much larger amperage and very close to in phase wave.

I don't agree with Omnibus ignoring inductive reactance, but just to show that his results have a issue, I'll use the same technique with Rms values.

1:  P = I^2 * Rt = .00347^2 * 52.1 = .000627 Watts
     P = V * I      = 6.55 * .00347 = .022729 Watts

2:  P = I^2 * Rt = .0533^2 * 52.1 = .148 watts
     P = V * I      = 6.44 * .0533 = .34325 watts

So these results show that there is no OU and that as secondary output increase so does input wattage.

Regards, Larry