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Overunity Machines Forum



STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

Started by PaulLowrance, December 04, 2009, 09:13:07 AM

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teslaalset

Quote from: exnihiloest on May 20, 2010, 02:40:14 AM
http://www.overunity.com/index.php?action=dlattach;topic=8411.0;attach=44825

This schematics is correct only in linear modes.
When a magnetic core is saturated as in Steorn motor, non linear resistances must be added in parallel with each L. The Steorn's measurement error is due to this simple fact.

Good point.
What you are referring to are core losses. When passing through the B-H curve (using negative and positive input current) the surface of the B-H curve represents the loss per cycle.
The two figures below visualize this. The red areas represent the energy put into the coil, the blue area represent the energy returned by the coils. The difference is the core loss.

It was my understanding that Omnibus used only positive current input at first instance.
In such case the only extra losses besides the ohmic losses are due to viscosity, see the red area in the third picture below. For high frequencies they will be hardly noticeable because viscosity delay is much higher than the cycle time of the input.

In case of low frequencies, of course, these viscosity losses will also occur when full cycle the B-H curve (twice, one for the positive side, one for the negative side)

Omnibus

Quote from: teslaalset on May 20, 2010, 07:00:45 AM
Good point.
What you are referring to are core losses. When passing through the B-H curve (using negative and positive input current) the surface of the B-H curve represents the loss per cycle.
The two figures below visualize this. The red areas represent the energy put into the coil, the blue area represent the energy returned by the coils. The difference is the core loss.

It was my understanding that Omnibus used only positive current input at first instance.
In such case the only extra losses besides the ohmic losses are due to viscosity, see the red area in the third picture below. For high frequencies they will be hardly noticeable because viscosity delay is much higher than the cycle time of the input.

In case of low frequencies, of course, these viscosity losses will also occur when full cycle the B-H curve (twice, one for the positive side, one for the negative side)

See, core losses are over an above the Ohmic losses. Therefore, any observed OU based only on Ohmic losses, as in the discussed here case, would be just conservative -- the real OU effect will be greater.

Omnibus

@teslaalset,

At your request I changed the load active resistance to 0.0607Ohms (measured) by adding in parallel another 4 of the 0.47Ohm ceramic resistors. The apparent OU effect was slightly lower. However, adding another air coil in series with the original 0.1192Ohm ceramic resistor and the original air coil the OU effect shot way up. Now, here we may again think that the inductance is to blame for an error in the measurement, however, take a look at the schematic diagram for this measurement -- the output current is measured by dividing the voltage across the active resistance R2 while the output voltage is measured across both the resistor R2 and the air coil R3. Seems the measurement methodology is correct which gives further confidence in the reality of the observed effect. I'm attaching here the Excel file with the data from this 80kHz, 10% duty cycle, sine wave experiment taken at -3.66V (-6.10 pulse generator reading) offset.

teslaalset

Quote from: Omnibus on May 20, 2010, 08:00:33 AM
See, core losses are over an above the Ohmic losses. Therefore, any observed OU based only on Ohmic losses, as in the discussed here case, would be just conservative -- the real OU effect will be greater.

Some background of this can be found in a nice Texas Instruments document, page 5:
http://focus.ti.com/lit/ml/slup123/slup123.pdf

Omnibus

Quote from: teslaalset on May 20, 2010, 08:22:49 AM
Some background of this can be found in a nice Texas Instruments document, page 5:
http://focus.ti.com/lit/ml/slup123/slup123.pdf

Thanks for the link. It is my understanding that per cycle the energy that characterizes those losses is only given by the area enclosed within the hysteresis curve. In any event, like I said, those losses would give an even greater OU effect if included in the energy balance discussed here.