STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[Groundloop]

@Omnibus,

I do not understand you? Did you not use resistors to measure
the input and output power to/from the coil?

Groundloop.

[Omnibus]

The resistors which I use are to measure the current (by measuring the voltage drop across these resistors and dividing their resistance into that voltage drop). The obtained heat in the output coil side of the transformer, however, is equal to the Joule heating of the resistor in question plus the Joule heating of the secondary coil itself (it also has Ohmic resistance). That isn't the entire heat obtained, however. In the energy balance equation, in addition to the Joule heat of the secondary coil and the Joule heat of the mentioned resistor, you have to add also the Joule heat developed in the resistor in series with the primary coil, the Joule heat of the primary coil itself and the Joule heat of the two additional coils I have added in series with the primary coil. All of that is output and that output has to be compared with the input (with the integrated momentary Iin*Vin, that is).

[lumen]

@Omnibus

I do wonder if the test you are performing is accurate when measuring only on the ground side of the device.
Do you think it possible to accurately test the primary on the input side in a similar fashion?

The reason I think this is because it would seem there could be some capacitive coupling between the windings in the transformer. This would tend to show up as increased output on the secondary and reduce the load on the primary (where you are checking).

It would also be likely that the capacitive transfer would also be optimal at some exact frequency.
If the input load were used in the calculations, then this could be eliminated.

[Groundloop]

@Omnibus,

OK, I got it now.

Groundloop.

[Omnibus]

@Omnibus

I do wonder if the test you are performing is accurate when measuring only on the ground side of the device.
Do you think it possible to accurately test the primary on the input side in a similar fashion?

The reason I think this is because it would seem there could be some capacitive coupling between the windings in the transformer. This would tend to show up as increased output on the secondary and reduce the load on the primary (where you are checking).

It would also be likely that the capacitive transfer would also be optimal at some exact frequency.
If the input load were used in the calculations, then this could be eliminated.

I would like to understand this argument better. First, as you can see all the voltages, both on the side of the input and on the side of the output coil, are measured against the same ground, as is the correct way of measuring them.

Further, capacitive coupling between the windings of the transformer seems far fetched to me. There may be such a thing but I've never heard of it. A reference or link would help.

Let's, however, suppose that there is such coupling. Understand first that I' calculating both on the input and the output side. The capacitive coupling would affect the phase of the I with respect to V and at some frequencies it might be very favorable. Then, if capacitive coupling brings about the effect let it be more. That not only wouldn't hurt but will favor the results and will explain additionally where the effect might be coming from.

Remember also that at the request of @gyulasun I placed capacitance in parallel with the input and I saw no effect due to this addition.