STEORN DEMO LIVE & STREAM in Dublin, December 15th, 10 AM

[LarryC]

In calculating these powers one should follow the physics of the situation. That's what determines the outcome. The voltage and current should be as they are, without messing up with them and the current in the Joule's law is to be squared. So far, as @broli says, the calculations are OK and what has to be determined is if the whole current goes through that resistance R. I've shown data that it really does and I'm working on further definitive proof which, as I said earlier, will post here as soon as I get ready.

So you are using Pin = V *I and Pout = I^2 * R. Because of ^2, Pout is basically an absolute value, but Pin is not absolute and has negative values half of the time.

Then you graph the absolute and non-absolute values and claim OU. Just the simple fact that Pin can be negative should tell you that this is not mathematically correct.

GB, is right. Using your methods, Omni power is everywhere.

Your Pin = 2.26E-06  Pout = 9.48E-06.

I changed your excel and made Pin absolute also and got the following values:
       Pin = 2.64E-05  Pout = 9.48E-06.
Oops, lost my Omni power big time.

Okay, I'm outer here for a while, got a big Omni ache. But, I'll be watching to see how you geniuses get that OU power out.


Regards, Larry

[broli]

 

[Omnibus]

So you are using Pin = V *I and Pout = I^2 * R. Because of ^2, Pout is basically an absolute value, but Pin is not absolute and has negative values half of the time.

Then you graph the absolute and non-absolute values and claim OU. Just the simple fact that Pin can be negative should tell you that this is not mathematically correct.

GB, is right. Using your methods, Omni power is everywhere.

Your Pin = 2.26E-06  Pout = 9.48E-06.

I changed your excel and made Pin absolute also and got the following values:
       Pin = 2.64E-05  Pout = 9.48E-06.
Oops, lost my Omni power big time.

Okay, I'm outer here for a while, got a big Omni ache. But, I'll be watching to see how you geniuses get that OU power out.


Regards, Larry

What you're doing is arbitrary. It is incorrect. If you do it right the OU will still be there.

[exnihiloest]

If you do it right the OU will still be there.

"I believe there is OU therefore there is OU".   

[Omnibus]

"I believe there is OU therefore there is OU".   

The opposite is true: "I believe there is no OU therefore there is no OU" and to "prove" that the likes of @LarryC will crunch the numbers any way it suits them, no matter how much in opposition to physics and reason that might be.