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Omnibus · June 30, 2010, 04:51:24 PM

Here's the 1Ohm plot showing negative slope of the input energy-time curve:

teslaalset · June 30, 2010, 04:51:36 PM

Quote from: Omnibus on June 30, 2010, 04:43:44 PM
@broli and @teslaalset,

I got it. Posted it in a couple of posts back but you probably missed it. Here it is for 5Ohms. For 1Ohm you got negative slope of the input energy-time curve.

I dont' get it

Can you tell us how exactly you calculated the OU factor?
If I look to the graph, input energy is higher than the output energy all the time.....

Omnibus · June 30, 2010, 04:59:38 PM

I'll do further studies but, recall, this follows the trend I observed experimentally. The 100Ohm was only giving me slight OU and as I went down the Ohmic resistance the effect went up getting even into the negative slope region. Also, recall the study with the caps. 300pF hardly showed any OU while as you went down in capacitance not only OU emerged but also the negative input slope popped up. @broli asked me to do some studies of these dependencies but my Excel crashed and now I'm struggling halfheartedly with it. Will do it as soon as the new Excel arrives

P.S How pathetic, the seller notified me after I contacted him that Microsoft has required some delay in shipping. But, how can that be since when tracking it in the USPS site it was stated that it was shipped but USPS never received it. Also I checked in Staples and they do have Excel 2010. So it has already been shipped. Weird. Anyway, let me not bother you with this mess.

Omnibus · June 30, 2010, 05:01:22 PM

Quote from: teslaalset on June 30, 2010, 04:51:36 PM
I dont' get it
Can you tell us how exactly you calculated the OU factor?
If I look to the graph, input energy is higher than the output energy all the time.....

Take a look at the slopes of the two curves -- you'll see the equations of the best-fitting lines on the right-hand side of each curve. The slopes give you the input and the output power. OU = Pout/Pin.

teslaalset · June 30, 2010, 05:02:34 PM

Quote from: Omnibus on June 30, 2010, 04:59:38 PM
I'll do further studies but, recall, this follows the trend I observed experimentally. The 100Ohm was only giving me slight OU and as I went down the Ohmic resistance the effect went up getting even into the negative slope region. Also, recall the study with the caps. 300pF hardly showed any OU while as you went down in capacitance not only OU emerged but also the negative input slope popped up. @broli asked me to do some studies of these dependencies but my Excel crashed and now I'm struggling halfheartedly with it. Will do it as soon as the new Excel arrives

P.S How pathetic, the seller notified me after I contacted him that Microsoft has required some delay in shipping. But, how can that be since when tracking it in the USPS site it was stated that it was shipped but USPS never received it. Also I checked in Staples and they do have Excel 2010. So it has already been shipped. Weird. Anyway, let me not bother you with this mess.

Don't get me wrong, I don't want to attack your work, I just want to understand it.

I assume you took the trend slope ratio's to calculate COP and anticipate on many cycles to continue this trend to obtain the real OU?

[edit]
Just missed your post above, thanks.