Mostly Permanent Magnet Motor with minimal Input Power

[telecom]

This is an interesting test,but what are the ruel's based around the test.?
Would this be allowed-we have a spring sitting under the 500g weight.If Luc can get the weight with spring into resonance,and the 500g weight is lifted that 2cm's twice a minute,dose that still count?-are we aloud to use the spring. If a spring is not an energy source,then i dont see why not. this would then become like a kid on a trampoline.

Hi Tinman,
I really don't know the answer:
On one hand, the spring will distort the actual output of the device, will make it higher;
On the other hand - this exactly what we want to achieve...

[telecom]

@ telecom, when I came up with this design 5 years ago I ordered many large 2" square by 1" thick N52 magnets to build a super powerful version of it.
I never did build it because most said it wouldn't give OU and then the topic died.
I still have at least 10 or more of these super magnets in the original delivery box in storage . Today they are worth a fortune compared to when I purchased them.
I guess it's time to open the box and build the thing to see the real results!

I was thinking to build one that's at least 8 inches wide by using 4 of these 2" wide by 1 " thick magnets next to each other. That way most of the coils outer magnetic field is used. Only 1" on each sides where I attache the guides would be lost compared to my latest design where only half of the outer field is used.

Luc

Hi Luc,
this should work really well, IMHO
Looking forward to seeing it!

[tinman]

Hi Tinman,
I really don't know the answer:
On one hand, the spring will distort the actual output of the device, will make it higher;

If a spring is not an energy source,but only an energy storage device,how will it make the output higher?
Think of the weight as an inductor,and the spring as a capacitor. All you need to do then is hit the right frequency of the tank circuit to gain resonance. Once resonance is achieved,we will get a large amplitude-in this case,the 1/2kg weight being lifted that 2cm twice per minute

To be within test guidlines,the 2cm lift would have to start from the point at which the spring is not compressed-just off the surface from which it will contact as the weight drops.If the spring is to compress 1cm,then the total travel of Luc's slide(coils travel) on his device would need to be 3cm.

Why the spring would allow the weight to be lifted more efficiently than if it wasnt there?.

The answer is simple. If there were no spring,and the weight was just allowed to hit the surface as it fell to a resting state,then energy is disipated from the system as noise/vibration. The spring removes this loss,and stores that energy that would have been disipated as noise/vibration,and returns it back to the system. So the spring wont actually distort the output,but it will make it higher due to less loss in the system.

[telecom]

If a spring is not an energy source,but only an energy storage device,how will it make the output higher?
Think of the weight as an inductor,and the spring as a capacitor. All you need to do then is hit the right frequency of the tank circuit to gain resonance. Once resonance is achieved,we will get a large amplitude-in this case,the 1/2kg weight being lifted that 2cm twice per minute

To be within test guidlines,the 2cm lift would have to start from the point at which the spring is not compressed-just off the surface from which it will contact as the weight drops.If the spring is to compress 1cm,then the total travel of Luc's slide(coils travel) on his device would need to be 3cm.

Why the spring would allow the weight to be lifted more efficiently than if it wasnt there?.

The answer is simple. If there were no spring,and the weight was just allowed to hit the surface as it fell to a resting state,then energy is disipated from the system as noise/vibration. The spring removes this loss,and stores that energy that would have been disipated as noise/vibration,and returns it back to the system. So the spring wont actually distort the output,but it will make it higher due to less loss in the system.

When weight is being lifted, we increase its potential energy.
When it drops, the potential energy becomes kinetic, which is being absorbed
at the end by the holding string(w/o the spring).
When the spring is underneath, it absorbs the kinetic energy into the potential energy of the spring when it compresses, and releases it on the way up, which helps to pull
the weight up. This will distort the actual performance of the device.

[tinman]

When weight is being lifted, we increase its potential energy.
When it drops, the potential energy becomes kinetic, which is being absorbed
at the end by the holding string(w/o the spring).
When the spring is underneath, it absorbs the kinetic energy into the potential energy of the spring when it compresses, and releases it on the way up, which helps to pull
the weight up. This will distort the actual performance of the device.

No,the kinetic energy isnt being absorbed by the string,it is being transformed into vibrational energy via the string through the framework of the device,and then to the bench the device is mounted on,and finally to ground(earth). The spring stores the kinetic energy that would be normally transformed into vibrations/vibrational energy/sound,and returns it back to the system apon spring decompression. Energy is never absorbed,it's stored or transformed.