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Overunity Machines Forum



Mostly Permanent Magnet Motor with minimal Input Power

Started by gotoluc, December 07, 2009, 05:32:38 PM

Previous topic - Next topic

0 Members and 11 Guests are viewing this topic.

TinselKoala

Quote from: tinman on August 20, 2014, 05:11:06 AM
Would be good to have some test perameters right about now.
So we could do it like this.
It takes 1 joule of energy to lift 1kg of mass 10cm high.
If we are setting the weight to 1/2kg(500g's),with a lift hight of 2cm,then we need 100millijoules.
A cap that has say 5000uf would then need 6.325volts in it to give us our 100mJ.Or if we have a 10000 uf cap,we would need only 4.47 volts in it to give us our 100mJ.

So Luc,if you can lift that 500g weight by 2cm using a 10000uf cap with only 4.47 volts in it-you have hit unity. If you need only 4.46 volts in the cap to do it,you are OU.

Hmmm.... what if I take a one nF cap and charge it to 15 kV and discharge that into a water arc chamber, full of water, with the bottom of the 500g "piston" in contact with the water? Or rather, since the arc will cut off before the cap is completely discharged, let's say I start with 17 kV and end with 2 kV still on the cap. If I can get 2 cm rise (or 2.2 cm) out of the 500g piston, will I have OU?

You have to be very careful with this kind of reasoning. It's almost the same thing that caused Peter Graneau to waste years of his life and millions of dollars of grant funding, chasing an imaginary unicorn through a dense forest of experimental data.

telecom

Quote from: Khwartz on August 24, 2014, 05:03:37 AM
Dear TinMan, I think you're on the Very Right path in term of Correct Methodology for o.u. checking :D Caps are Very Great to provide accurate maths on energy delivering or input :)
How can be they so great if voltage varies and there is always a small charge remaining?

tinman

Quote from: telecom on August 24, 2014, 09:45:57 AM
How can be they so great if voltage varies and there is always a small charge remaining?
A cap with a set value(uf) and set voltage,will have X amount of energy(joules).After running the test,IF there is any voltage left in the cap,you simply calculate the joules of energy left in the cap,and subtract that from the amount you started with in the cap befor running the experiment.This is a very accurate way of seeing how much energy you used in the test.

tinman

Quote from: TinselKoala on August 24, 2014, 07:13:46 AM
Hmmm.... what if I take a one nF cap and charge it to 15 kV and discharge that into a water arc chamber, full of water, with the bottom of the 500g "piston" in contact with the water? Or rather, since the arc will cut off before the cap is completely discharged, let's say I start with 17 kV and end with 2 kV still on the cap. If I can get 2 cm rise (or 2.2 cm) out of the 500g piston, will I have OU?

You have to be very careful with this kind of reasoning. It's almost the same thing that caused Peter Graneau to waste years of his life and millions of dollars of grant funding, chasing an imaginary unicorn through a dense forest of experimental data.
There is no reason i can see that this wouldnt be a valid test TK. Why dose this example you give,give reason for caution? Do you believe that your 15kv in your 1nF cap is enough to cause that greater explosion,that it will raise that 500g piston 2.2cm?. i doubt that very much. Infact,it is very hard to get an ark in water,and i dont think 15kv at 1nF would do anything at all.I have tried to get a spark plug to work under water,and even with that small spark gap and 25kv ,i couldnt get it to spark.

ramset

TinMan
perhaps water purity will effect this? [very pure distilled or reverse osmosis]


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Chet
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