Mostly Permanent Magnet Motor with minimal Input Power

[TinselKoala]

Here's how I did it back in the Steorn Orbo days.
I measured the force (from the digital force gauge) and the distance (from the micrometer head adjustment) while running various levels of current through the coil.

Back off distance until at some "start" point. Apply current to the coil. Take force readings every 0.1 mm as you crank the micrometer head to make the magnet in the head of the force gauge get closer and closer to the coil. Take readings going in the other direction as you go back up. Then set a new current level, and repeat the measurement series. Plot the data.

In this way I was fully able to characterize the Orbo "core effect" and to show just how little reduction in attractive force was really needed to make the Orbo run at speed.


Inductors in parallel and in series:
Inductors add like resistors. That is, for inductors in series, the final inductance is just the sum of all the individual inductances. For inductors in parallel, the relationship is more complex.

the total inductance of non-coupled inductors in parallel is equal to the reciprocal of the sum of the reciprocals of their individual inductances

IOW inductors in parallel add up in the same way as resistors in parallel.

http://en.wikipedia.org/wiki/Series_and_parallel_circuits#Inductors_2

[gotoluc]

Thanks for your post TK

I don't see or maybe don't understand the point of making a curve chart when my coils push or pull force is equal (does not change in any position) throughout its 1 inch of travel?

This is where my design blows away a standard solenoid.
As you know, solenoid are not capable of pulling over 2.5kg at the beginning of their stroke and maintain the same pull force for 23mm of travel and only consume 0.43 Watt continuous 24/7 without the coil even getting warm.

Luc

[TinselKoala]

I'm a little confused here. I thought you  didn't know how to  measure these pull forces and you wanted to know how to do it. So I am puzzled that you now say you know what the forces are, you know they are constant over an inch of travel, etc etc.

How are you measuring this pull force? What is the smallest difference in force your method can reliably detect? Can you show a plot of force vs. distance along a well defined path, that can be compared with other coil configurations along the same path?

[synchro1]

Take a well wrapped bifilar solenoid coil connected serially with a welding rod core. Hang a steel carving knife by a string. Aim the center of the coil at the dangling knife and pulse it like you would a Leedskalnin device shorting the coil across a 12 volt battery. Watch what happens to the knife. Next, move the coil further away and try it again. This laser dimension magnet wave was broadcasted and received by Tesla at a distance of 40 miles from his downtown laboratory to West Point on line of sight. This was the first wireless transmission in History!. The broadcast and receiver coils were identical and both were grounded. The wave carried power that Tesla believed traveled through the ground! 

I re-discovered this effect by accident as I've recounted in the past: My first shop wound bifilar coil, 350 turns of 22 gauge, with welding rod core slid around ten feet to collide with a cutlery box that was drawn an equal distance along my kitchen counter, from one direct short pulse. The experience was traumatic! The magnetic force produced this way had nothing whatsoever to do with the customary D.C. Joule to coil flux ratios. Try it! 

[Khwartz]

Thanks for your post TK

I don't see or maybe don't understand the point of making a curve chart when my coils push or pull force is equal (does not change in any position) throughout its 1 inch of travel?

This is where my design blows away a standard solenoid.
As you know, solenoid are not capable of pulling over 2.5kg at the beginning of their stroke and maintain the same pull force for 23mm of travel and only consume 0.43 Watt continuous 24/7 without the coil even getting warm.

Luc

Luc, could you indicate the frequency of the run up and down while pulling 2.5 kg 1 time (lifting) on 2 (lifting and dropping)? (I suppose you run it against the gravity, to talk about "kg", so mass, otherwise only about "pulling force" and so "newtons"...).

Because if I am not mistaking, if you lift 2.5 kg the first second, that you not energise at the second time and let the mass dropping, so no consumption of input power, you would have overunity, cause:

P [W] = W [Joule] / T [second]

P [W] = (F [Newtons] * Displacement [m]) / T [second]

P [W] = ((M [kg] * Gravity acceleration [m/s²])* Displacement [m]) / T [second]

so:

P [W] = ((2.5 [kg] * 9.84 [m/s²])* 0.023 [m]) / 1 [second] = 0.566 [W]

and:

COP = 0.566 [W] / 0.43 [W] = 1.32 ^^

Note: if you get that king of result while energising both times (lifting and dropping), it is even more promising cause we didn't care in the previous calculation of the work we may harness while dropping! in fact, it would correspond to a COP of (few mechanical losses aside):

COP ~= (2 * 0.566 [W]) / 0.43 [W] = 2.63