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Overunity Machines Forum



MAGNET SHIELDING

Started by 24hosting, December 15, 2009, 11:12:14 AM

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Rapadura

#35
April 16, 2010, 07:19:28 AM
Quote from: Low-Q on April 14, 2010, 10:45:50 AM
Inside a halbach tube the magnetic flux is uniform. The steel ball is actually being forced all directions at the same time.

No, no, that's not a halbach tube...  In the drawing bellow, that's just an ordinary plastic tube, used to force the ball to go only forward and back, not sideways.

The idea is that the ball can be attracted by the attractive side of the Halbach array, and after passing the array a little, it will not be attracted by the other side, as it would be in a normal magnet, because that's the non-attractive side of the Halbach array.

jonifer

#36
April 16, 2010, 08:16:31 AM
On forсe diagram - see the not obvious peak. Area size S1=S2 (Power left = power right)
F - force along X axis.

Rapadura

#37
April 16, 2010, 03:52:58 PM
Quote from: jonifer on April 16, 2010, 08:16:31 AM
On forсe diagram - see the not obvious peak. Area size S1=S2 (Power left = power right)
F - force along X axis.

To be honest, I didn't understand what you said...

So, what will be the behavior of the ball? Passes the Halbach array a little and then is attracted back? Don't pass the Halbach array and gets stuck just in front of the extremity of the array?

Charlie_V

#38
April 16, 2010, 11:11:54 PM
It would just get stuck before it entered, unless you gave it a good enough kick, but then it would roll back.  Even if you had magnetic monopoles you couldn't make an overunity device because the moving part would just find the area of least magnetic repulsion (if in opposition, like North North) or area of greatest magnetic attraction (if in attraction, like North South).

Case in point, using electric charges (which are monopoles) you can make a stator composing of a ring of balls, each ball charged to slightly higher electric field values.  A ball in the rotor can be charged with an equal E -field potential.  All the rotor will do is find the area of least Electric field and sit there (since the rotor has the same potential as the stator).  You'd have to change the E field values of the stator to get it to move.  In doing that you would induce a current and use power.

jonifer

#39
April 17, 2010, 12:38:49 AM
conditions of overunity is S1>S2 or S1<S2 (movement direction). In this model S1=S2. "S" -square under line.

http://www.youtube.com/watch?v=Md4gikM9Ezs
not working by the same reason
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