Overunity.com Archives is Temporarily on Read Mode Only!



Free Energy will change the World - Free Energy will stop Climate Change - Free Energy will give us hope
and we will not surrender until free energy will be enabled all over the world, to power planes, cars, ships and trains.
Free energy will help the poor to become independent of needing expensive fuels.
So all in all Free energy will bring far more peace to the world than any other invention has already brought to the world.
Those beautiful words were written by Stefan Hartmann/Owner/Admin at overunity.com
Unfortunately now, Stefan Hartmann is very ill and He needs our help
Stefan wanted that I have all these massive data to get it back online
even being as ill as Stefan is, he transferred all databases and folders
that without his help, this Forum Archives would have never been published here
so, please, as the Webmaster and Creator of these Archives, I am asking that you help him
by making a donation on the Paypal Button above.
You can visit us or register at my main site at:
Overunity Machines Forum



Magnet motor in Argentina

Started by Jdo300, March 19, 2006, 12:46:30 AM

Previous topic - Next topic

0 Members and 2 Guests are viewing this topic.

_GonZo_

Well calculations done...? :-[ it does not work.

Why:

Let me see if I can explain it correctly.
If all trhe magnest were down the motor will not move OK
If one magnet is moved up then it will move. The force that creates that movement is equal to the repulsion force of that magnet we have moved up.
Then the rotor in that movement have to move up the next magnet, but there is an spring that keep it down and the force of that spring to keep it down is the same or bigger than the repulsion force of that magnet.

So the rotor when it turns have to make the work of lifting one magnet that is compresed down with the same force as the rotor is geting from the other magnets, so no move will hapen as there is looses in earth systems...? :(

Hope it is clear.


Jdo300

Hello All,

If I may put my two cents worth in; I have been contemplating the operation of this motor and thanks to _GonZo_ for clearing up the ideas behind how it runs. Actually, I think there may be one small factor you are leaving out. When all the Stator magnets are down, the entire system is in equilibrium, yes, however, when one of the stator magnets are displaced, you are essentially having the combined repulsive force of all the other magnets pushing the rotor out, not just one of the magnets. Check out the diagram I made below. How I picture it is like this:

1. While the motor is in balance, the stator magnets behave as one giant radially magnetized ring magnet with the North Pole facing in.

2. Once a piece of this ?ring? is removed the fields are unbalanced and you have essentially one large curved magnet with its north pole facing in. We all know from playing with magnets that when you repel two magnets against each other, the side of the magnet that the other magnet is closest to will be the direction it is repelled in (sorry for the bad description, refer to my duiagram). In other words, look at the rotor as being a single magnet that is on one end of this giant, curved, North Pole magnet.

3. Because the rotor is close to the break in the giant magnet, it is repelled towards that break, but not just by its neighboring magnet, but by the combined field strength of all the stator magnets since they will behave more or less like one single magnet.

So it is very possible that the combined force of the other stator magnets pushing the rotor may be enough to overcome the resistance force needed to lift the one stator magnet as the cycle continues. This could be possuble if the springs used to hold the magnets down are tensined just enough to balance out the magnetic force plus a tiny bit more. That way, you really wouldn't need much force to move the magnets.... It makes me think of Butch LaFonte's balance fixture. When big forces are balanced, it doesn't take much to unbalance them.

Again, just my two cents  :)

God Bless,
Jason O

_GonZo_

I understand perfectly what you mean, and I understand that it may be dificult to understand, let me make you some questions:

In a ring of lets say 10 magnets and each one is aplyin a force to the rotor of 1N/m when you take out one of them, how much force is aplied then to the rotor?

And in order to keep one magnet in its position how much reaction force you need to aply if it is repeled 1N/m?

Omnibus

Stefan, the three-magnet rotor is being pushed from the position it has in the picture to the left, away form magnets M1, M2 and M3 (M4 up). As the rotor turns towards the position of M4, the magnet M4 is being dropped while the magnet M5 is being raised.

The presumption is that the force that drives the rotor away from M1, M2 and M3 is so strong that it not only moves the rotor and overcomes all friction but is also enough to lift magnet M5.

There is one more problem, though ? the opposition to the motion of the rotor by the falling M4. While M5 may be slowly upped so it won?t oppose the further motion when the rotor gets in the position as in the picture (but this time against M2, M3 and M4), the magnet M4 has to go down somewhat suddenly at the right moment. If M4 goes down too soon it may oppose the motion efficiently and the rotor will stop.

hartiberlin

Hi Guys,
this motor is really puzzling me !
I think it could work !
The springs are very important !
I think here are 2 systems at work each superimposing !

1. Imagine no magnets at all inside this motor, but springs being there
to push down the stator versus the rotor. ( again no magnets inside rotor and stator)
Now, if we move the rotor Made of a triangular ramp up and down) one stator further,
we lift M5 and M4 goes down.
That means we have to apply the same force for lifting M5 as M4 gives us back
via its spring by pushing the rotor to the next position.

Imagine a triangular lifting and pushing down ramp rotor setup without magnets.

To push up M5 (actually moving it out of the stator rowline)
needs the same energy as the rotor gets from M4 when the spring
of M4 pushes the downramp part of the rotor down. ( M4 aligning again with the stator rowline)


Thus the forces are in equilibrium and only the mechanical losses prevent the rotor to move
on after a few cycles, when you give the rotor a spin. But without mechanical losses
(spring and friction losses) the rotor would move on indefinately....
So you see, this part of the system is there and only has small mechanical losses.

2. Now the second parts with the magnets come into play !
As Jason pointed already out, the whole stator stack acts as a big magnet
creating a very big force versus the rotor magnet, so it is easy to push the magnet
with a factor 15:3 in the case of the Torbay drawing into the clockwise direction.
So this 15:3 force just must be a bit ?bigger than the initial uplift spring force
plus the mechanical losses Q.
Also the rotor gets also back the stored spring energy of the spring of M4,
it will propelled even further more.

So I think there is just a mechanical setup required of the right spring force
constants and the right number of stator versus rotor magnets.

I think this motor is pretty genuine, but I also think the presented prototypes
in the pictures are not able to generate 2000 Watts, maybe 10 to 100 Watts,
but not more when you look at the size of the generator and the lamp connected....

But with a bigger size I guess one could get into the KiloWatts range !

Regards, Stefan.
Stefan Hartmann, Moderator of the overunity.com forum