LaFonte Group can turn off permanent magnet without work

[synchro1]

http://www.youtube.com/profile?user=Lidmotor#p/u/2/Otz-C-q_RwQ

@Butch,

            Here's a hyperlink to Lidmotor's ¨Mag Lev Bobin Motor¨; Levitating Reed Switch Pulse Motor. The motor consists merely of a Reed switch in series between the tiny copper wire air core coil and the double A battery. His unit has a power potentiometer in series as well. Simple as pie! Take notice of the levitation axle.

[LarryC]

The following scope shot is the test of the toroid, transformer design shown in reply #53. A 100 Ohm resistor is placed across the primary coil (10 Ohms). The rpm is 2,997 and the input wattage to the AC induction motor is 26. With just the rotor along, the input wattage is 20.

The trace is a little weird and could be due to the fact that the magnets are not centered on the toroid, only about 65 percent as the rotor is larger than the toroid. Also, the magnets should be larger as they do not cover 50 percent of the arc, only about 30 percent. I have a smaller rotor on order so that will improve.

As Butch said there is insignificant clogging and no effect on the input wattage or rpm when the load is open or closed. Lenz is in the system, but the rotor does not see it.

I see this as an improvement over Flynn's PPMT generator as it requires input to the coils to switch the flux flow.

The second picture shows magnets for a wind turbine. These plus Lafonte Group switcher technique, but using the design that I showed in reply #53

Regards, Larry   

[gyulasun]

Hi Larry,

Thank you for this, very very interesting.

Could you measure the self inductance of your output coil and based on that could you connect a series capacitor of the same reactance the coil has at the above loaded RPM?  This cap would make the waveform much more sinusoidal, thus true effective value of the AC output could be had.

Alternatively, would you use a full wave bridge (if you agree) and then drive a load, the loss of the FWBR could be counted in.

What if you would use a 10 Ohm load resistor instead of the 100? It would be good match to the coil, together with a series  resonating capacitor at the loaded RPM?

Thanks and sorry for the several wishes...

Gyula

PS: IF the inductance of the coil changes as the rotor moves you could use an averaged L value of course.

[LarryC]

Could you measure the self inductance of your output coil and based on that could you connect a series capacitor of the same reactance the coil has at the above loaded RPM?  This cap would make the waveform much more sinusoidal, thus true effective value of the AC output could be had.

Alternatively, would you use a full wave bridge (if you agree) and then drive a load, the loss of the FWBR could be counted in.

What if you would use a 10 Ohm load resistor instead of the 100? It would be good match to the coil, together with a series  resonating capacitor at the loaded RPM?

PS: IF the inductance of the coil changes as the rotor moves you could use an averaged L value of course.

No inductance meter. Did do the FWBR test, and it showed steady voltage close to the V rms shown by the scope. About 1.5V lower due to diode loss. 

Really liked the 10 Ohm resistor test.

In the first pic you can see that with a Vmax of 2.40 and Vmin of 2.36 gave a Vrms of 1.55. This is a high percentage for rms. In my other test with the 100 Ohm resistor the rms was around 8 with a Vmax of 20 and Vmin of 20.

In the second pic you can see the full wave form showing the voltage staying high and low for a much longer period of time.

Regards, Larry   

[Butch LaFonte]

http://www.youtube.com/user/LaFonteGroup
Thanks guys,
Butch