GENERATOR- YOU DO THE IN/OUT POWER MATH

[Omnibus]

And a heavier than the air device can't fly (as they tought in the XIX Century)... Wow, Santos Sumont was really a rebel...

If E=MC², what happens to so called "conservation of energy"? Becomes conservation of "mass-energy"... Good trick...

No, they didn't. This is a misnomer. Birds were heavier than air in those days too and they were seen to fly back then. That's a wrong analogy for the suppression of progress.

[Low-Q]

You might be right about all of that. I am currently constructing a minature full wave bridge rectifier.
I will dump all the AC output into it. Sure there will be some power loss but it then becomes very easy to compare input to output power as both are now DC.  Hi frequency AC is tricky to measure correctly.

It would be way much faster using a long conductor so you can measure the amps away from the magnet. You'll get the result right away. No rectifier is required (Unless I missed something with your rectifier plans).

Vidar

[e2matrix]

Hi.

I put a new fuse in my analogue meter.

Input is 9VDC @ 0.075A.
Output is 33VDC @ 0.080A

When i measure DC mA, the magnet slows down a lot, is this because it's such low amperage that even measuring it is taking too much away ?


Gary.

That would possibly depend on how close your meter was to the magnet also.  There might be enough metal or copper in it to effect the magnet speed.  And an analogue meter will put more load on a circuit than digital normally would.  But either way it sounds like you've got a winner.  Based on your numbers:
Input=   0.675 Watts
Output= 2.64 Watts
COP = 3.91   

That's assuming no errors in measurement.  I'd sure like to hear what Tom is getting also.  I do think this concept has good potential. 

[mscoffman]

You can’t just switch your meter to Current and measure it. You need to measure
current through a load resistance. But what value load resistor?

Measuring Power correctly;

What you want do is to measure the voltage across a load resistor using a DVM.
Stick the voltage meter reading number into an equation, then adjust the resistor
value until you get maximum Power. Or else use a variable resistor , then measure
the resistance setting after it has been set to maximize P.

Since P=E*I and E=I*R it makes P=E^2/R we want to adjust our load R so
that P (power) is maximal in the equation P=E^2/R. That means adjusting R
around until the calculated P value becomes maximum (not E maximum). We
then don’t need to measure I the current at all.

What one is doing here is matching the source impedance (AC resistance) of
the coil to the load resistance of the resistor. Maximum power is transferred
between the generator and the load when the internal impedance of the generator
matches the impedance of the load. We want to know what the max calculated
P is in milliwatts.

---

I’ve noticed that even in cheapo DVM’s the resistance of the meter in
measuring current can often affect the load. This wouldn’t happen but
the meter cannot display enough leading zeroes (have enough accuracy)
when displaying small currents. So they boost up the resistance so that
the meter gets more voltage to work with…But that insertion resistance
then affects the circuit.

---

Self Running;

What one wants to do now, is down convert your 33 volts or whatever you get
under load that produces max Power. Down convert it to 12 voltsDC across a big
cap then use one of those automobile lighter inverters to step it to 110/220Volts AC.
Then use a wall wart power supply to supply input to your motor…If you do this
carefully and get this right the system should self run. If your auto inverter has an
conversion efficiency of 30% then you need a system COP gain of 3.0 to offset it.
Your particular inverter’s efficiency may vary. If you start the system to run on
utility power then switch it to internal the capacitor will either charge up - overunity
or discharge for long enough time where you can see what is going on.


:S:MarkSCoffman

[DeepCut]

That's really helpful, i know little enough about electronics let alone proper testing methodology.

Toms new video is up now showing 40 LED's being lit (brightly) :

                       http://www.youtube.com/watch?v=i3Cpv4Lxdyw&feature=player_embedded

He's outputting AC until his rectifier components arrive.

Total watts used to light the LED's is 24 and he's only inputting 4.86 ...

My setup can't compare at the moment because my axel is high-friction until my bearings arrive.

I'm off to test with load resistors ;+}


Gary.