Can energy double?

[FreeEnergy]

deleted

[Rapadura]

The car is the same weight of the ball? Will the ball really fall?

[FreeEnergy]

yes the ball would fall but not at free fall speed. i can be wrong though.

[Rapadura]

Hmmm... Maybe the ball falls, but at slow speed, so the kinetic energy will be far less than the kinetic energy of the ball falling without having to pull the car.

No, energy won't double.

[Zhang Yalin]

Experiment：

Set a generator and an iron ball weighing 1kg at one edge of a table.
Connect the ball with a toy car weighing 1kg placed at the opposite end of the table top. The distance between the ball and the car is 10m.
Drop the ball. Pulled by the ball, the car travels from one end of the table top to the other, colliding with the generator to produce electricity.
At the same time, the colliding force of the iron ball makes another generator set on the ground produce electricity, with approximately a half potion of which the ball would be lifted and the car pulled back. Thus the device would circulate on end.
Friction=0.2kg,  g=10 m/s2ã€,
The accelerating speed of the iron ball and the car is:
F=ma, F=G-f=1×10-2＝8N, a=F/m=8/1=8(m/s2)
The end speed of the iron ball and the car is:
Vt2=2as＝2×8×10＝160, Vt =40（m/s）
The kinetic energy of the iron ball and the car is:
Ek=1/2mvt2 ＝1/2×1×160＝80(J)
The energy consumed to set the iron ball back in place.
The energy consumed to set the car back in place is negligible.（At most， E=fs=2×10＝20J）
Ep=GH＝10×10＝100（J）
The energy gained:
E=80×2－100＝60（J）ã€,