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Overunity Machines Forum



Inductive Kicker or Bug?

Started by DreamThinkBuild, April 27, 2010, 06:29:56 PM

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innovation_station

i got a tonne of thease little light bulbs ... 

this is what i was gonna do with em ...  lol

i have probally 1000 of em  6vdc 25 ma ...  lol  use the mag synced transformer wjt take the output ... to the bulb then to the base of the fet ...   build a second jt to fill the driveing caps to working voltage or use a cam board  then fire the fets to a coil however your fets must be rated for THE FLYBACK VOLTAGE YOU WORK WITH OR THEY BLOW

drop a bulb on the output .. as your low inductance LOAD !
ist

the bulbs inductance as my meter reads it is 00.00 h
resistance of a bulb is 17.8 ohm
capatiance is OL over load

hummm

bulb is 120vac  60w
To understand the action of the local condenser E in fig.2 let a single discharge be first considered. the discharge has 2 paths offered~~ one to the condenser E the other through the part L of the working circuit C. The part L  however  by virtue of its self induction  offers a strong opposition to such a sudden discharge  wile the condenser on the other hand offers no such opposition ......TESLA..

THE !STORE IS UP AND RUNNING ...  WE ARE TAKEING ORDERS ..  NOW ..   ISTEAM.CA   AND WE CAN AND WILL BUILD CUSTOM COILS ...  OF   LARGER  OUTPUT ...

CAN YOU SAY GOOD BYE TO YESTERDAY?!?!?!?!

Magluvin

Hey DreamThinker
I looked at the circuit you presented.  I cannot say for sure, but it looks like when the switch disconnects from the inductor, that it is singing on its own. I think that the program has a hard time with diodes and having disconnects with the diode still connected to the active passive device, the inductor.  Probably in most circuitry, these situations would not be in place and all components are connected at both ends to some other circuit.

In your sim, the switch on the right opens, and the inductor should continue the current flow through the diode, but then it can not pull from the diode in the opposite direction, say bemf, if any energy is left after dumping what it had through the diode. But I seriously doubt that the inductor would retain any potential across its leads after the switch was opened.  I am supposing here.   BUT

Lets say that the switch opens, yet the inductor, with its inertia mechanism, forces more electrons than it has holes for through the diode to the source, and it may do so easily, being that the source is accepting all incoming.
Now, What might go on in the inductor, with its oscillations, if it had many open holes? Missing electrons.  Would that affect the self capacitance and the inductance, and could it be an ingredient needed to pull from the vacuum?  I never really thought of any of this before now. Im just spittin it as I type here. 

Charge the coil as you show, then disconnect the coil from the circuit on the opposite side of the diode, and the inductor pushes many electrons through the diode and they cannot get back to the inductor. The coil should be 1 big positive charge just waiting for its babies to come home.  Would it just be a static charge? Static.   Is a positive electrode on a battery static when not connected to a load?

I would not put this one down till some experimenting is done, on a safe level.  At first I fully assumed that when the inductor lost its top connection, that how could the inductor retain a potential across itself connected 1 ended to a diode that will only provide and exit and no come back.
Maybe the program does not know what to do with this rectified static, and it shows it some way some how.
I would say give it a shot. Start with low inputs at first and see what a couple pulses will produce.
If it is static, if you provide an earth ground with a spark gap to the static inductor, maybe the babies wil come home, except they will be someone elses babies. lol

I will post this on your thread and here at Energy Amplification

Mags

Magluvin

Hey dreams

I messed with your circuit with manual switches and could not get what I expected. I have found the program at times can develop a bug in the code if something goes awry during changes. Then I rebuild. If you save a code with a bug that develops, it will retain the anomaly. 

Try to rebuild the circuit from scratch and see if there is a difference, being that you wont be making any changes and already have the correct values.    Cus if you have a bug, and keep developing on that bug, all changes, like putting a cap on the inductor will still have the bug.

I would try the same from scratch and see what haps.   =]

The main reason I think you have a bug in the code is the fact that the 1 ended inductor, when switch is open has potential and it is not really part of the circuit at the time.        But my bugs are similar in that an unconnected leg can cause a funkyness in the code.

Good luck

Mags