N-Pole Motor Trifilar Design

[mscoffman]

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Could it be that as the magnetic fields collapse at each stage and
provide surges of bEMF, it may be collected in additional capacitors
on each battery?

Please recognize that a single inductor has two terminals and in
the Bedini Motor one terminal is pinned at 12Vdc with low
impedance. So the the other terminal is going to go massively
plus and then the BEMF is going to take that back down -  not
massively minus voltage. So it's one terminal relative to the other.
Just as the voltage trace shows. If the 200VDC+ was pinned lower
somehow the BEMF might even take the voltage into negative territory

The AB secondary coil of the other hand seeks it own DC level so the
BEMF will actually be negative on it. The bridge rectifier will take care of that.

The definition of an inductor is: "it doesn't want current through it to change"
so when it starts, it has zero current and slowly builds up (LR time-constant).
Until by-george it is going over the 12 Volts orginally supplied! Then the
transistor cuts off as the magnet starts moving away from the pole and
the current now begins to collapse flowing the other direction pulling down
from the spike's high voltage. If never really goes negative due to the DC
bias from the transistor.

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Note:
Your non-motor circuits don't show the coil tied to (+) but to battery (-)
so your diode circuit is equivalent to an emitter coupled transistor circuit.
You are going to need to take that into account if you "motorize" the switch.

:S:MarkSCoffman

[geotron]

mscoffman,
The concepts you're bringing across aren't wholly understandable to
me at this point, although I thank you for your help.  Eventually
when my knowledge reaches a certain point I'll likely have a more
valuable response; in the meantime though I think I'm able to grasp
the essence of what you're getting at, except for when you refer in
your note to an 'emitter coupled transistor circuit' - I'm not really
able to picture such a thing in my mind.

I've gone ahead and transformed my printout of Daftman's bifilar
motor diagram into a schematic form, and will be studying it a bit
as I have done with the one drawn by Bedini.

Due to my previous confusion with using my radioshk meter to help
explain which direction energy flows through a diode VS their outter
markings, it may be that I've thrown in an error or two.  My
interpretation of how the coils are labeled with "ST" & "SR"
indicated to me that these mark the beginning of the wind, so this
is how I have drawn it -

[nievesoliveras]

@geotron

There is a mistake on the storage battery diode direction. The cathode goes to the positive and is pointing away.

Also there is a mistake on the transistor diode. The cathode should point to the base and is pointing away.

Jesus

[mscoffman]

@geotron

There is a mistake on the storage battery diode direction. The cathode goes to the positive and is pointing away.

Also there is a mistake on the transistor diode. The cathode should point to the base and is pointing away.

Jesus

Agree.

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a) the diode attached to the base is to *keep* the trigger coil from driving
the base to a negative voltage. This is because electron "charge storage"
will build up on the base's (parasitic) capacitance. That would make the
transistor slow down when switching. The line on the diode is the line
the arrrow points to in the symbol. It means positive current flows the
way of the arrow. DVM Ohmeter leads are sometimes reversed polarity
because of an age-old convention. Use a battery powered LED to be
certain about the polarity.

b) The little waveform on the first schematic is what the collector voltage
looks like on a scope. There is no negative voltage so because the free
end of the battery is stacked up -  only when the spike goes above
24VDC will the "charge" battery be active. (again only on the AB coil
connection is there any negative voltage) Because a transformer
does not set DC bias or DC base voltage - a transformer only speaks AC
(except for DC saturation current flowing through it which we are not
using here) What you have to see is that there is no negative voltage
available to the "charge" battery. So it's really the positive spike (both
up and back down) that the "charge" battery intercepts. The charge
battery can't supply any power through it's diode.

:S:MarkSCoffman

[geotron]

I thought those might have been pointing the wrong direction.

When I was working on setting up my Gray's Tube, getting the
diode to function properly by blocking the high voltage from
escaping from the tube with a 30kv diode, I first hooked it up
in the standard direction - the stripe on the side pointing
into the tube and it didn't block anything.  There were massive
electrical discharges inside gapping over the electrodes, passing
through the diode and disrupting things on the other side.

Only when I reconnected the diode to with the strip facing opposite
the direction into the tube did it block the high voltage from
escaping.  This in addition with my non-standard multimeter has
caused me much grief in confusion.

Currently I'm in the process of building a coil-winding jig with the
use of a sewing machine motor - plenty to work on at this point.
Once it starts shaping up I'll begin posting some information on it,
but for now let me see if I've got any edge on the bifilar coil motor.

---------

1) Similar to how the transistor is used in trifilar version, the
flux generated on the trigger coil is directed into the base, although
this time through a series of a resistor and a potentiometer (which
has me guessing).

2) The path is then connected between the (+)Primary through the
start of the power coil and into the 1N4007.  This lights up the
neon bulb and then continues into the (-)Primary, the Trigger Coil
from the opposite polarity as it is being charged by the magnet,
the 1N4001 into the Base, and the Emitter.

This is the extent of my understanding thus far.  It is substantially
different to the point where I'm getting a bit confused.  It seems
as though with the (+)Primary leading into the base through the Neon
it would permanently keep the transistor in an 'on' position.