Can electrons flow in opposite directions on the same wire, see schematic!

[kmarinas86]

I will try to make this as simple as I can.

When you connect to the center of the two batteries, that junction becomes 0-Volts, AKA ground or earth, in respect to the other two poles, the far left pole becomes -1.5V and the far right +1.5V. You should also notice, if you have connected both motors correctly, that the two motors spin in different directions (I think but I may be wrong), this is because the polarity at one end is mirror image to the other. You should also notice that each motor is only receiving 1.5-Volts.

Disconnect the vertical center green wire, then both motors should spin in the same direction, this is because now the far right positive end is 3-Volts, in respect to the far left negative. With that wire disconnected, one motor will speed up if the other one is labored or stalled, very handy for a differential effect in a model car or robot.

That kind of circuit is simply a voltage splitter, very handy for reversible speed control circuits.

How can you have current going out of the positive on one side and current out of the negative in the other? Batteries don't work like that.

What do you think would happen if you had two rectangular circuits, each with a motor and a battery operating, and then decided to connect a little wire between the hot side of the first one and the cold side of the second one? Would one motor reverse direction? I think not. I understand that is not actually the same circuit, but you could take four plates of copper and arranged them like an H like you have in my example and some how build it so you could then rearrange them like H tilted over like in your diagram, then would the motor reverse? Never. Not in a million years.

The ability for the battery on the left to power that motor directly is largely dependent on the size of the conductor relative to your current. If you use very wide conductor plates, it would easy for the opposing currents to be split, but if they were so thin, then it would be more like attaching a meter across with high impedance, and you basically get nothing going through there. Somewhere in between those two situations you would have something like a ground that is 1.5V less than the rest of the circuit.

Your diagram below:

[the_big_m_in_ok]

... This is not strange, it just may look that way. See the link below of a dual supply from the mains. It's the same thing essentially.
Dual supply diagram
.99

.99 may have a point.  An astable multivibrator using a push-pull inverter can do the same thing as the diodes in the schematic.

http://upload.wikimedia.org/wikipedia/commons/3/39/Astable_multivibrator.png

--Lee

[Bulbz]

How can you have current going out of the positive on one side and current out of the negative in the other? Batteries don't work like that.

I never said that, I said the junction where the batteries meet act as a ground. I think you misunderstood me.

Get yourself two batteries, and one motor, connect the two batteries in series and connect a wire to the point where the batteries meet (the center). Connect that wire to on side of the motor, then connect the other side of the motor to one of the open ends of the battery assembly. The motor will obviously spin and if you connect it to the other end of the battery assembly, it will spin the opposite direction.

I know that is right, I was taught it in college yonks ago. It is also the configuration that is used in a push-pull amplifier.

[kmarinas86]

I never said that, I said the junction where the batteries meet act as a ground. I think you misunderstood me.

Get yourself two batteries, and one motor, connect the two batteries in series and connect a wire to the point where the batteries meet (the center). Connect that wire to on side of the motor, then connect the other side of the motor to one of the open ends of the battery assembly. The motor will obviously spin and if you connect it to the other end of the battery assembly, it will spin the opposite direction.

I know that is right, I was taught it in college yonks ago. It is also the configuration that is used in a push-pull amplifier.

Where is the AC in the diagram?

With batteries, wires, and nothing else, those motors cannot be AC and be made to run properly.

For the motor on the left to run the opposite direction, you're asking the direct current from the other side of the battery to power the motor.

Your diagram:

[Bulbz]

Where is the AC in the diagram?

With batteries, wires, and nothing else, those motors cannot be AC and be made to run properly.

For the motor on the left to run the opposite direction, you're asking the direct current from the other side of the battery to power the motor.

Your diagram:

AC ?, there is no AC and the motors aren't either. I was simply trying to describe as simply as I can that current doesn't run in both directions in the center wire. The circuit is simply a voltage divider !

[me]Bangs head against wall[/me]