Over Unity Lightbulb

[elgersmad]

What you are trying to say, is that the 67 Amperes of current doesn't exist between the capacitor and coil.  The operating Voltage is not at 100 volts RMS, and that if that were the primary winding of a transformer, it wouldn't work or be there.

Well, there is the simulation for you, and if you build the circuit, the AC power source, is only using 31.6 mA to keep all of that power there in the tank circuit.

Since, the bulb is only an open secondary by design, it will light up very brightly, with all of that energy.  Why?  Because, the secondary looks like there is no load on it.  The primary only looks like an inductor, and is stuck that way.  Any time another parallel tank circuit reaches it's peak output voltage and current, the next is fired up into resonance, and as a result Q of the next circuit is working together with the Q of the previous.  When it's fired up, the impedance of the parallel tank circuit goes high, and that makes the secondary of the first stage look or seem open due to the second tank circuit reaching resonance peak output values.  There's nothing more untested than your imagination.

[elgersmad]

In addition to that, I have maintained, that you cannot extract the energy if you short the secondary, or load the secondary of any of the stages, especially the last stage.  I have maintained, that you can extract heat from the transformer cores, or use it to produce light with a bulb designed to operate as an open secondary winding.

At the point that it is over unity, you are extracting all of the energy in a manner that doesn't effect the operation or the condition of this circuit in operation.

[elgersmad]

My spice simulator isn't showing me true AC readings correctly.  So, the Current Meters and the Voltage Meters are constantly changing values.  At the moment of the snapshot of circuit operation, there is 3,361.8 watts of power between the capacitor and coil, and only 1.68 watts being drawn from the power supply powering it.  That is without any extra stages adding to that effect.

In reality, I applied 100 Peak, which 200 volts peak to peak, or 70.7 volts RMS.  The readout on the Oscilloscope is in RMS.  Which is really 141.4 volts peak, 282.8 peak to peak or 100 volts RMS.

When you do the math and have meters that work properly, there's 100 volts at 100 amperes RMS present between the capacitor and coil, which totals out to 10KW.  There's approximately 740 watts for every horsepower.  Eventually, the core can heat up fast enough to keep a coolant running at a high enough number gallons per minute to keep the core within it's curie temperature range.  At the same time, you'll be able to use the transformer's core like a nuclear reactor's fuel rod, just by keeping it from overheating.  The heat extracted would then travel to a heat exchange unit that utilized the thermoelectric generator cells.  It would look allot like a radiator where one both sides of a flat rectangular pipe lined with thermoelectric cells.  If it were not for the thermoelectric cells it would look just like a car's radiator after that including the fan blowing the heat off of the thermoelectric cells.  Oddly enough, heavy water that's been loaded with minerals has a much higher boiling temperature, and you could use it to move the heat via a fluid out of the ferrite core.  As long as the coolant is non-magnetic, and non-conductive, it will pass with very little resistance to flow and fluid friction shouldn't change during operation.   If the coolant were conductive or ferromagnetic, it would get trapped in the core, and the pump would see the on state of the circuit as a kind of fluid brake. There are so many different configurations of heat exchanges, I would suggest an all ceramic heat exchange unit, and loading every other tube with ferrite slugs, and only passing fluid through every other tube.  A toroid core wouldn't be so easy to work with, but a U core or an E core could be.  The method would have to account for empty space that reduce the permeability of the form due to the volume left to coolant.  Ferrite does tend to get hot.  But, the quantity of ferrite would be much smaller than you'd normally see for that much power due to the use of a coolant other than air and the effecincy of the heat exchange.  That adds up to allot more math than I'm doing for a light bulb.

[elgersmad]

I highly suggest that if you design the circuit that you use cores in sort of fashion.

1st stage Permeability of 2
2nd stage Permeability of 200
3rd stage Permeability of 20000

Or a similar set of ratios.  Any permeability greater than one will cause the magnetic lines to follow the core and magnetic circuit, so all you are really looking is something greater than one.  If 1.1 were used, then 110, and 11000 would be used.  When you have a series of step up transformers, you need more resistance in the winding of the previous stage's secondary, than there is in the next stage's primary and for the most part, nearly equal inductances.  Making the Q value of every secondary much lower than the Q of primary windings of each stage.  When you build the real circuits, you'll see that helps.  Those core values are ideal for 1:10 step up transformer turn ratios.  If your step up turn ratio is lower, then the difference between cores will be lower.

[elgersmad]

Anyone know what propaganda is?

Propaganda is this circuit, when you don't need Uranium to do that.  When you tune it, you simply tune it up to the resistance of the filament of the bulb at it's resistance during operation.  When you first turn on a lightbulb, it's a short circuit, and the filiment's resistance is near zero, then as temperature rises, so does the resistance of the filiment.  So, here's a propadanda link:
Written to keep you in the dark, when ferrite would work better.