Selfrunning HHO system with 400 Watts additional output

[questioneverything]

Heat, radio waves, cell signals, even the magnetic field around the power lines are forms of radiant energy. It's energy that's radiated instead of transmitted.

[Omnibus]

Heat, radio waves, cell signals, even the magnetic field around the power lines are forms of radiant energy. It's energy that's radiated instead of transmitted.

The implication was that there's some other energy that Faraday's law of electrolysis cannot account for. No, there is no such energy even if you call it radiant energy.

[questioneverything]

The implication was that there's some other energy that Faraday's law of electrolysis cannot account for. No, there is no such energy even if you call it radiant energy.

There is another energy he did not account for. When a di-pole is resonated it does have the ability to pull in outside energy from the quantum field. It's the entire grounds of scalar energy charging batteries.

[Omnibus]

There is another energy he did not account for. When a di-pole is resonated it does have the ability to pull in outside energy from the quantum field. It's the entire grounds of scalar energy charging batteries.

No, there is no such energy. That's nonsense.

[mikewatson]

We seem to be tripping over physics here, water electrolysis is conventionally overunity, the excess energy comes from environmental heat absorbtion, the theoretical maximum efficiency is 120%, the excess 20 % comes from this environmental heat. Commercial water electrolysis baths operate at close to 100% efficiency.

See this reference Penner and Icerman, Energy, volume 2 page 135, Addison Wesley 1975.

Conventional electrolysis  absorbs 68.315 kcal per mole of water electrolysed and is the Enthalpy change for this process.  The minimum energy required for electrolysis equals the the Gibbs free energy change. Which is related to the voltage E required to implement electrolysis.
E = dF/23064 n  volts  (23064 =96500/4.184)                1 calorie = 4.184 Joules
n = 2 number of electrons per joule of water electrolysed.
dF = 56620 cal/mole of water electrolysed.

Voltage for electrolysis E = 56620/23064*2 =1.23 volts at 300 degK

The energy efficiency of electrolysis at 300 deg Kelvin is 120% the extra twenty percent comes from external heat, (the electrolyte cools) also the ideal voltage at 300 deg K  is 1.23 volts and this potential falls with increased absolute temperature.
However:-
The enthalpy change dH for water electrolysis under standard temperature and pressure is
68315 calories and
The voltage E for this
E= dH/23064n  = 68315/23064*2 = 1.48 volts at 300 deg K
This voltage is where the electrolysis is ideally 100% efficient and no heat is sucked from the environment. This is the so called thermo-neutral voltage

Unfortunately the converse is also true:- the hydroxyl fuel cell is theoretically 80% maximum efficiency.

So, for hydroxyl gas production towards 120% efficiency , clearly the cell should be operated around 1.25 volts and electrolyte concentration and plate area adjusted to give the required current.

Mike