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Overunity Machines Forum



Hydro Differential pressure exchange over unity system.

Started by mrwayne, April 10, 2011, 04:07:24 AM

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GreenHiker

LarryC.- I was playing with your Travis Effect Calculator and saw that if you ran the four risers through the same volume calculations you used for the pod, and added all 5 together, it comes up with virtually the same number (16,082 vs. 16,065) as in in your original total.

mondrasek

Quote from: LarryC on June 16, 2012, 09:50:13 PM

They increase the head for the large force provided by the most inner riser.


The water head at any pod or riser is only due to the difference of the height of the water on the outside vs. the inside of that member.  That is the only head that acts on each individual member.  I believe the calculator spread sheet is missing a "Next layer" line under Riser 4 where a good portion of that "large force" needs to be subtracted.  The majority of the total lift is actually coming from the Pod and Outermost Riser?

I think the way this spread sheet is laid out might be confusing.  The buoyancy of each member is the Surface Area x Head on that member only.  So the biggest member (Outermost Riser) always has the largest Surface Area and possibility of the largest head.  Each inner member has less Surface Area and less possible head.  So the possible force coming from each member must be:

Outer Riser > Inner Riser > Next Inner Riser > ... > Pod

Please correct me if I'm wrong.

M.

LarryC

Quote from: GreenHiker on June 16, 2012, 09:59:17 PM
LarryC.- I was playing with your Travis Effect Calculator and saw that if you ran the four risers through the same volume calculations you used for the pod, and added all 5 together, it comes up with virtually the same number (16,082 vs. 16,065) as in in your original total.
Good catch, very interesting observation. So a 4 Riser Travis system is basically equal to the lifting force of 5 separate Archimedes's systems, but with almost 5 times water inlet requirements on Archimedes's to move the system up the same height and almost 5 times the physical footprint.

Travis has stated several times, the more layers, the more efficiencies.

Thanks, Larry

mrwayne

Hello all,
I am heading out of town for a week, I want to congratulate you all.

First; any of the three methods you introduced will reflect the upward force properly - well done.

Second - stroke length is a decision you make on how much of the "Mechanical" ideal you wish to use.

In the model you are working with - overlapping walls (ring walls and Risers) are best when you are at the bottom of a stroke
The over lap is the most you can expect at anypoint in the stroke - it changes as you stroke.

Simply plan to utilize the overlap at the end of your stroke - set that as your combined load - force - or resistance
There is no loss - (other than utilization) because you can  not create more head than the load anyway.

So - on your small model - I said short stroke - now you know why.

Next comment:

You are at the same point at which our Engineers (who where hired to disprove our system started to say omgosh).

Let me help you jump ahead a little - in our system the head -like Larry mentioned - travels up with the stroke - this results in a special condition at the end of stroke -
Namely - all the energy you put into the system is still there - the load is up - and removed - but the buoyancy - "head" - is still intact.

You limited the stroke - unlike other buoyancy systems we do not fill -then - float -then DRAIN and then sink - as you have discovered - moving the head creates a sink condition. The sink condition is directly related to the static load - as one of you mentioned - well done.

Now - we move the head - into the other Zed (equalization - free flow as we call it) the first one does not sink during equalization it sinks (during stroke of the other Zed).

We reserve a large portion of the head (neutralizing the weight of the system - we also do not expand the air in the system (Much) as one of you stated - well done.

Now in the equalized postion - we use the pressure in the lowering Zed to supplament the Stroking Zed -
Guess what this does for efficiency..........very exciting

We add weight to the riser and split the desired force - like this with our 6000 pound force model - 2000 pounds lifts weight - returned in the system (exhaust - lowering Zed transfer),  2000 to fuel the internal operations and 2000 pounds absolutely free.

In short - our three layer system has a total of 1/3 the Ideal - absolutely free.

Do not get trapped into thinking you have to exceed the Ideal of a system to achieve OU - that would be magic - our system is simple physics - seen in a new light.
When you wrap this together - you will see why - every engineer who comes - is so excited to join our work.

Well done men, ladies'

Now you know what I saw in the hot tub back in 2008 - in the Travis Effect - pretty cool, and why we dropped everything and persued this - against all odds.

Please e-mail me when your OMGosh moment hits - I am honored by your work, and will include you in our historical journals (with permission) and possibly work together in the future of Clean FREE Energy.

jwtravis5@peoplepc.com

Wayne Travis

neptune

First can I say a big thank you to mrwayne for dropping by. Although I am gobsmacked by the intellect and intuition of some of the members here, we are going to need all the help we can get. And who better to help us than the Main Man.
   I had a little idea when I was out riding my electric bike today. As I was passing a farm, I was looking at a large tank used to store diesel fuel for tractors. On the side of this tank was a home made device used to check the fuel level in the tank. It consisted of an adapter fitted into the tank wall near the bottom. From this, a clear plastic pipe extended up to the tank top. where it was open to atmosphered. So the level of fuel in the tank was the same as the level of fuel in the pipe.
    Suppose we built a ZED from non-transparent materials . We could use this idea to "see" the water level in each compartment, but the upper end of the pipe would have to return to the compartment through the top. This would be possible if all risers were fixed together at the top, as I believe they all rise and fall together anyway. Any comments ?