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Overunity Machines Forum



Hydro Differential pressure exchange over unity system.

Started by mrwayne, April 10, 2011, 04:07:24 AM

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0 Members and 105 Guests are viewing this topic.

MileHigh

Mondrasek:

I admit that I am not following the thread but your answer is still insufficient.  You are apparently claiming an "energy gain" from the lift of one ZED can take care of moving the water over to the other side of the system?  Know what it sounds to me like?  It sounds like you are just moving the fairies further up the chain of events.  No fairies needed to move the water back and forth between the two cylinders because the two ZEDs take care of that.  So who takes care of the ZEDs?  Even if you have an explanation for that it just means that you are moving the fairies along yet again.  Eventually you will hit a wall and there will be no place for the fairies to go.

Here is my challenge to you and the other believers:  Stop beating around the bush and ask Wayne what the output of the system is and exactly how he is measuring it.  He won't answer me and always plays the "wounded and harassed inventor" card.

You believe in his system?  Then again, I challenge you to ask Wayne what the output of the system is and how he measures it.

Put aside the spreadsheets and the buoyancy calculations for a week and ask about the output.  Supposedly Wayne is on the verge of doing a demo so why not ask him?

It's too easy to just "play free energy calculations" and pretend that the over unity power output is a given.  You "know" that it's there so you don't have to ask about it.  You would prefer to focus on the "science" of the calculations.

Shift your focus on the power output of the device for a while and ask about the tangible real-world results.  Are any of you believers willing to step up to the plate and ask Wayne?

MileHigh

mrwayne

Quote from: LarryC on July 21, 2012, 11:48:32 AM
Thanks Wayne,

Additional information from you always helps. In my next example, I was going to add air compression and how it has a combined effect the more layers you have. With my previous example I just wanted to make sure everyone understood the basics, before my next example to show the difference in Input volume and obvious time of input as the number of Layers increase.

In your little model, what is the Pod Height, Pod Diameter, Material thickness, Clearance?

The attached water height calculator based on Outside retainer water drop used 71,30,.25,.20. It used .28 for the drop as I was confused about your .28 diff is .52, not .56, then the .40 on the total differential. 

The water input is set to ideal, so that would be part of the small difference if you are starting from Initial Pre-charge. In playing with this calculator, I noted that it can get the same total differential with different water layer values as long as you balance it properly. The calculator used volumes based on each air/water gap square inches and calculates from outer water to inner, which forces the water/air column's to align based on the previous channel air expansion/compression.

I wasn't sure about releasing this one again , since I corrected it, as it is quite confusing. It shows a lot of extra calculations that could have been part of the formula's, but it helped me to better understand the parts that make up the whole.

The calculator xls is attached last.


Regards, Larry
That was an internall adding error, thanks for catching it.
I will go back and fix it.

Wayne

GreenHiker

Just visited the local zoo with my kids.

Most visitors are respectful. They go to the zoo, see the animals, read and watch the presentations, and they learn.

Others go to the zoo and end up throwing rocks & sticks at the animals for their own cruel entertainment.

The internet is the same way…


Tom

mrwayne

Good work Larry,
You have shown how the "concentration" of the "Travis Effect" works.
I might suggest that we move on to the next portion of the system.
The next phase is to understand how much Head is transferred to the second Z.E.D
Things to consider - The weight of the risers and added weight - they allow the system to sink when partially charged (head)
When You calculate how much (minimum) head it requires to float - amount of weight - you have the minimum exhaust pressure.
Next - you need to Know what your stroking pressure is - so your weight plus your production load - maximum head needed.
Take the average of the two pressures - and this gives you the post free flow pressure.
The value of the free flow is the head at max (end of stroke) to the post free flow pressure.
The value of the remaining exhaust is the post free flow pressure to the Minimum head pressure (sinking pressure)
The head less than the sinking pressure always remains in the Z.E.D and never needs replaced.
This is a good start.
Our pressure is:
Minimum 5.0,  8.4 max, and 6.7 post free flow.
Since the true input cost to each side it the diffirence between these pressures and the Max - this is very important.

Wayne



mrwayne

Larry,

Some where read and lost track of  - You asked about our system:

The Pod is 707 si or 30 inch diameter 6 feet tall
All our walls are .198 thick and clearances are .25 inch
This system is three layers.
And Yes  the arangement of the diffirentials within layers - very much effects the lift.
(Wise observation) - More diffirential in the outer layers increases the lift - think about how that effects our exhuast pressure (when the inner laers have dropped the diffirential)
Remember - very little movement happens in the outside layers...............
Well done.
Wayne