Hydro Differential pressure exchange over unity system.

[MileHigh]

Mondrasek:

You have this big honking groaning behemoth of pistons and valves and compressed air and displacing water and a programmable logic controller with a digital display but nobody can state what the power output is!  There is something wrong with that picture!

MileHigh

P.S.:  Here is a link for you to contemplate:  http://www.choicepaintballguns.com/bulk-co2-hpa-tanks

Wow!  100 cubic feet @3000 PSI and it's only $289 USD!   

[LarryC]

At the risk of arousing the further wrath of mondrasek and the other workers, I have to say that what is described here sure sounds to me like something material, not "just" energy,  is being "produced" from nothing ... You can't have air pressure that increases or that is exhausted to some other place, without increasing the amount of air... the number of molecules, the mass of the air.
You are removing mechanical energy from the system to keep it moving against friction etc. But you are also exhausting something from one Zed to the other. How is what is exhausted, replenished, so that the mechanical losses are made up, with extra left over?  I know, I know.... from the exhaust of the other Zed.

Hi TK,

Thanks for reminding me, with the many inputs from Wayne today, I haven't shown the difference in Input volume and obvious time of input as the number of Layers increase. Please see attached. Do you see how the Travis effect layers have a big advantage over regular buoyancy?

Both Archimedes's pod and Archimedes's +  3 Layers have the same starting and ending PSI. The Archimedes's + 3 Layers have a clear advantage in reduced volume input and time.

The figures shown in the first attachment are from the second attachment xls spreadsheet.

Regards, Larry

[neptune]

Milehigh. Whilst I am thoroughly disappointed that you will not  study this device, For the sake of keeping the peace, I will try to answer your three questions. The answers I will give are purely my own opinion based entirely on information gleaned from the thread.
1. This is a small proof of concept model, and is designed to output up to 500 watts. The relationship between size and power output and size is not linear, and I believe that Wayne said that a 25Kw model would occupy a space the size of a parking space. In the present model, a high percentage of the output is being used to run monitoring equipment. I believe that leaves about 40 watts running a lamp load. Even if that figure was 5 watts, we still have overunity.
2. The output device appears to be a permanent magnet alternator, of the wind turbine type.
So the ouput, after rectification, will be DC.
3 No idea how Wayne measures the output. Much more relevant is how Mark Dansie measures the output. I have little doubt he will tell us in due course. Those are my opinions.

[MileHigh]

Neptune:

It's almost like you guys are out of the movie The Manchurian Candidate.  You are so uncomfortable when someone asks some very basic questions when in fact you should freely answer them without turning things into a psychodrama.  It's a form of peer pressure bordering on self-brainwashing.  It's right out of the Twilight Zone.

I really don't have to know all of the specifics to ask my questions.  Alleging that I am "beating my wife" as some sort of quasi comical segue to avoid answering the question yet again is ridiculous and it's playing into the "bad guy" angle yet again.  What the hell?

I can feel the discomfort here, why?  You need to do some searching to try to answer that question.  Not even being able to admit that you can't answer the questions shows how deeply ingrained the peer pressure and discomfort level is.  You should work on deprogramming yourselves, seriously.

Thank you nonetheless for trying to answer my questions.   I will "reformat" your answers if you don't mind into what I am really asking:

How much power is output by the device?

A:  Between 40 and 500 watts.

In what form is the output power?

You did not answer or misunderstood my question.  You said, "The output device appears to be a permanent magnet alternator, of the wind turbine type. So the ouput, after rectification, will be DC."

Based on your response, my preliminary conclusion is that he output power is in the form of a rotating shaft.  My confidence would be increased if there are any references to this in the thread.  Strictly speaking, the question has not been answered.

How is the output power measured?

You indicated that you don't know the answer to this question.  Based on what you say above, it's possible that it may be measured by having a generator drive a load and then measuring the electrical power dissipation in the load.  Again, I am speculating, and you haven't answered the question.

So you could only answer one of my three questions.  I am not singling you out by stating that and my assumption is that it's the same story for most of the other participants in this thread.

Finally, look at your quote, "No idea how Wayne measures the output. Much more relevant is how Mark Dansie measures the output. I have little doubt he will tell us in due course. Those are my opinions."

This is an example of the discomfort and the peer pressure bordering on collective brainwashing.  I am assuming that you have been an active participant in this thread from the beginning and yet you have no idea how the output power from the device is measured and apparently you don't even want to know how the output power is measured.  How is that even possible?  I can also infer from your responses that you are not sure what form the output power takes.

Again, I am not the "bad guy" and I refuse to be made to feel like asking about the output from this device is somehow a bad thing to do.  There are a lot of issues for you guys to think about.

MileHigh

[neptune]

1.The output power is between 40 and 500Watts
2.The intermediate output is in the form of a rotating shaft, being the output shaft of a hydraulic motor. This motor is then used to drive the aforementioned alternator .
3. We have not been told how Wayne measures this output . If you wanted to measure the output at the hydraulic motor, a Prony brake would do the job.


I do not speak for anyone but myself, hence my pointing out that these are my opinions. It is of no concern to me whether you beat your wife or not. There you go. three plain answers to three plain questions.