Hydro Differential pressure exchange over unity system.

[mrwayne]

To Replicators -
Wall extension will not hurt - and for later expansion of the system they help.
But you will find - after you work through the set up, practice, and stroke (up and down) - you will lower the water volume in the outer layer.
p.s. if you try to stroke to far - overflow will continue to be an issue.
Wayne

[mondrasek]

Well the tint worked pretty well.

[TinselKoala]

Looking good, mond!

A couple LEDs inside the inner pod, a few clear plastic rulers from the dollar store or WalMart, a spring fish scale and a simple lever system to make it read "push" instead of "hang" when you want it to.... and with your input piston.... or simply an elevated "IV bottle" type means of obtaining a known head pressure for injection...... and you are ready to make some meaningful measurements.

[TinselKoala]

.

[Red_Sunset]

Seamus,

I realise such abstactions might be difficult for people who only think in terms of concrete physical devices with real dimensions. The good news for them is you don't need to

I would guess that is where we differ, if I can not visualize it, I have problems to deal with it. The number analysis in a previous posting was based on a process flow that originated from a visualization based on known physics principles that represented the actual build and working model in Wayne's lab.

I think the following statement is why we diverge

The 'general' approach works without needing to analyze any specific configuration of a device at all.

If we always look with the same eyes and use the same approach, we will always see the same thing or the same experience. This is not a fertile environment for innovation. 
Could you agree that a different or new angle could make us see something we did not see before, often just a simplification of a more complex problem will do that. Once this "new" is seen (visualized, recognized, discovered)  we can still process it in the known traditional way.

*1 - If you do not agree, we have no need to discuss anything further.
*2 - If you agree, you would see why I would have an issue with your statement

I believe the reason that you are on this forum and still following this topic, is that deep down there is a faint believe of possibility of the impossible. We can complement each other, I got the looks, you got the brains.
I would guess that you are a mathematically inclined and would have modeled the zed system in numbers.  Can you share your math findings in a post ?

A look at the Zed process flow,
It all has been said and described before by Wayne, but let me expand zed process flow from one of Wayne's posting's, from a few months ago. Maybe this is easier to read with understanding

1.. The layered buoyancy device has the ability to stroke (go up) with great force and short stroke.
2.. We stroke @ 8psi, "we start and finish @ 8 psi".
3.. The lifter was held at the preparation stage before stroke and also at the top of the stroke.
4.. The lifter is loaded with RiserWeight and Payload
5.. We stroke @ 8psi
6.. At the top of stroke we remove the payload
7.. The lifter remains under the duress of 8psi. that is still the same force to lift the riserweight + Payload if the travel would allow it. it can not travel further up because it is held by a stopper
8.. So the lifter can only go down,  to let it go down we pull the water plug at the bottom of the Z#1 water column, this is connected to the other zed (#2) pod area (z#2 water column bottom) and like any U bend, the water levels will equalize over both zeds.
9.. After equalization, the stroked lifter remains up, it did not descend, we need to help it
10.. So we pump water over to #2, it needs water in any case because we intend to make it stroke later (the zed in see-saw)
11.. While we pump, the zed#2 lifter remains stopped (locked)
11.. At a particular point,  zed#1 will come down to its initial start point (the lifter was only prevented from rising further, not from descending)
12.. With Z#1 at its starting point we keep on pumping to make z#2 stroke
13.. This half process cycle ends with Z#2 stroke completed and Z#1 at its starting point

As your positive contribution to this topic, 
Please model mathematically what happens in this process (z1 stroke to z2 stroke) for both zed and please share it in a post
You can choose any model, doesn't matter if not optimized, the principle wouldn't change,
Prerequisite:
When it comes to energy,  invested energy to start with is one Zed at "equalization" and one at "full stroke"

Regards, Michel