Hydro Differential pressure exchange over unity system.

[TinselKoala]

Please... let us review. Energy is conserved, it cannot be created or destroyed, only changed in form. What comes out equals what goes in, minus losses. Whether you believe this or not is beside the point and irrelevant for what follows.

In the Systeme Internationale, the system used by engineers and scientists worldwide, the unit of ENERGY is the Joule.
One Joule of ENERGY has the units Newton-meters, or reduced all the way down, the units of kg-m²/s² .  One Joule of energy is the energy you need to supply to lift a one Newton weight (about a hundred and two grams ) to a height of one meter, and is the same energy you get back when you drop that weight.
http://en.wikipedia.org/wiki/Joule

One joule in everyday life is approximately:
the energy required to lift a small apple one metre straight up. (A mass of about 102 g = ¹⁄_9.81 kg)
the energy released when that same apple falls one metre to the ground.
the energy delivered by a 1 watt solar panel every second.
the energy released as heat by a person at rest, every 1/60th of a second.^[6]
the kinetic energy of a 50 kg human moving very slowly (0.2 m/s).
the kinetic energy of a tennis ball moving at 23 km/h (14 mph).^[7]
Since the joule is also a Watt-second and the common unit for electricity sales to homes is the kWh (kilo-Watt-hour), a kWh is thus 1000 (kilo) x 3600 seconds = 3.6 MJ (Megajoules).

That is ENERGY.  It also has the same units as WORK.



Power is measured in WATTS. A watt is One Joule Per Second. A WATT is a RATE OF CONSUMPTION, dissipation, usage... whatever... it is a RATE. If you have an appliance rated at 1000 Watts, like an electric heater, it dissipates 1000 Joules every second that it is turned on.
The kiloWatt is a RATE of a thousand Joules of energy per second. The kiloWatt-HOUR, then, is that rate multiplied by the number of seconds in an hour. A kiloWatt-hour is the same thing as (1000 Joules/second) x (3600 seconds) = 3.6 megaJoules of energy.
http://en.wikipedia.org/wiki/Watt

A person having a mass of 100 kilograms who climbs a 3 meter high ladder in 5 seconds is doing work at a rate of about 600 watts. Mass times acceleration due to gravity times height divided by the time it takes to lift the object to the given height gives the rate of doing work or power.^{[notes 1]}
A laborer over the course of an 8-hour day can sustain an average output of about 75 watts; higher power levels can be achieved for short intervals and by athletes.^[1]
A medium-sized passenger automobile engine is rated at 50 to 150 kilowatts^[2] – while cruising it will typically yield half that amount.
A typical household incandescent light bulb has a power rating of 25 to 100 watts; fluorescent lamps typically consume 5 to 30 watts to produce a similar amount of light.
A typical coal power station produces around 600–700 megawatts. A typical unit in a nuclear power plant has an electrical power output of 900–1300 megawatts.

I've shown in previous posts what 20 kW means in hydraulic power. So.... does it really seem plausible to ANYONE that a 20 kW ZED system, working ONLY BY GRAVITY (including buoyancy which is just gravity misspelled)  AND SHIFTING WATER WEIGHT.... can produce 27 horsepower (more really due to inefficiencies) of hydraulic power to turn a standard hydraulic motor driving a standard 20 kW generator.... in a space the size of a "toolshed?"
It does not, to me. Drive a hydraulic pump with a Volkswagen motor... sure, then we have no problems. Drive it with the shifting weight of some water, and you WILL need the equivalent of a 30 foot high waterfall flowing at a rate of 58 gallons per SECOND, or more, in mechanical power to feed to the pump or rams providing the pressure and flow to drive the hydraulic motor driving the electrical generator.

[TinselKoala]

http://diy.stackexchange.com/questions/2616/what-level-of-electrical-service-should-i-order-for-new-construction

One hundred amp service at 120 V is 12 kW. 200 amp service at 120 V is 24 kW.

http://www.macfarlanegenerators.com.au/power-calculator.php

20 kW is nearly 27 horsepower of mechanical power.

Where in a ZED is that power going to come from?  Using the online calculators and the "animation", you can actually compute the volume and pressure of each hydraulic cylinder in the total circuit..... or you could if you knew the diameters and strokes of the cylinders. OK, so you have some stage of the process that is 960 percent efficient.... you STILL have to provide more than 27 horsepower to the hydraulic motor powering the generator!! So somewhere in the system, there must be, if Mister Wayne's claim is true, something that turns 3 horsepower from the sloshing floating parts, into 27 horsepower of hydraulic fluid flow and pressure. Where is this component or system? It's sure not in the animation or the patent application.

OR.... even more implausibly, if you follow Mister Wayne's "explanation" of using One unit of the "production" to run the system leaving Nine units NET of the production for the consumer.... then there has to be around 30 horsepower "produced" total, so that three can run the system and 27 can be used for running the 20 kW generator. More, actually, of course, because the hydraulic motor and the generator are not 100 percent efficient.

Where does it come from?

[TinselKoala]

Indeed, 960 percent does not tell you how much out he can get, it might be very little,, or things may have changed and it could be a lot bigger output.

I always thought that hydraulic generators were convenient but not so efficient,, just me I guess but I would take the output and use it another way, like my simple mechanical rectifier, why not just go straight to torque out?

The question Minnie asked, and that Mister Wayne answered in the "faqs" section of his website, is how big a zed system would have to be to run a house. Mister Wayne answered with a lot of words, mentioned 10 kW, 20 kW and 30 kW units, and in the website promised that units to run houses would fit in the footprint of a "toolshed". I've shown that a modern home needs at least a 20 kW supply, unless the owners are solar energy fanatics and read by candlelight at night. He has spoken many times "as if" such 20 kW output units existed or could exist. In this entire discussion I am addressing the issue of the possibility of the existence of a 20 kW output HDPE system, not one with "very little" output. I don't care if the Zed advantage is 80 percent, 160 percent or 960 percent.... something inside there is going to have to provide at least 27, and probably more like 40, horsepower to whatever is driving the 20 kW generator. How do you get around that fact? It doesn't matter, the Zed could be a miracle black box full of angels of God on treadmills or a fusion reactor running on bacon drippings .... the generator needs 27 horsepower at the shaft to make 20 kW electrical output. Or did Mister Wayne invent an overunity generator as well, that he's keeping secret just to make me look silly? I notice that he did not choose to answer me with a "YES" answer when I asked him if he had now, or EVER HAD, such a system operating at 20 kW output. To me... this is an honest way of saying NO that attempts to save face by not actually saying "no".

How are you going to turn the generator with your "torque out" from your mechanical rectifier?  Go ahead and assume a 100 percent efficient hydraulic motor if you like.... that is the 27 horsepower figure required to make 20 kW that I computed above.. If you use real world numbers like the 65 percent of an actual hydraulic motor, you need even more gpm and pressure to produce it. Do you have a "simple mechanical rectifier" that can produce torque out, continuously rotating a generator, with greater efficiency than a real hydraulic motor? If so, you should contact some hydraulic systems manufacturers right away and quit wasting your time with Mister Wayne.

[TinselKoala]

TK, 24 kw is 1 kw for 24 hours,, just thought I would let you know.

2500 psi is not a volume and the ZED puts out psi and volume, lastly your numbers would seem fair if you were only using gravity as your source then the lighter fluid could do less, but if not using gravity as your source then the difference does not matter.

Are we just sweeping this under the rug, or do you get it correctly, now?

http://answers.yahoo.com/question/index?qid=20080124151747AAWHDxc

[TinselKoala]

Hey TK,,  simple mechanical rectifier.

http://www.overunity.com/10629/simple-mechanical-rectifier/

The one posted on this site is only one of the possible configurations, and the clutches can be had in over 300 lb\ft strength,, well that was a few years ago.

It does not need to be gear to gear either.

This configuration to me showed the simple relationship the best, and yes this is the finger toy I used in some play time experiments

It is apart, I have used some parts for this and that and a few interesting experiments along the line of what MoRo is playing with.

Nice. I'm using almost the same system (half of it anyway) on my top secret Gyroscope Forced Precession AntiGravity device, implemented with the one-way clutch bearing and main rotor shaft from an Align T-Rex 450 electric helicopter. This enables you to use a hand crank to drive the precession axis by making small gentle back-and-forth movements with the crank lever, while the system rotates faster and faster on the precession axis, the little clutch bearing grabbing and releasing the shaft, grabbing and releasing, depending on the direction of the crank motion. Then when you stop cranking, the clutch allows the shaft to continue rotating with a small drag penalty. I didn't have the patience or the need to make it a "fullwave" system that would drive forwards on both back and forth motion of the crank, though, and I'm using a cogged timing belt and pulleys, not gears, but same principle.
I hope I'm not infringing on your patent !!
And forget you read that, it's supposed to be a secret.

These one-way clutch bearings do add measurable drag in the "freewheeling" direction, though, so I imagine in your system that in each direction, you are not only pushing the rotating part but also pushing against the drag of the unlocked clutch.

ETA: So you are obviously familiar with gearing and what happens to power and speed with gear ratio changes. The same input power can provide lots of torque at low speed, or high speed with little torque, on the output. And our rectifier systems can only add power to the shaft if they can turn faster than the shaft is already turning, and provide more torque than the shaft is resisting with. Depending on the generator you are going to have to turn it a couple hundred RPM at least and you will have to provide the required torque. If you gear up the speed in your system, you lose torque, unless you've also invented an overunity gearbox. 
Zeds rock back and forth pretty slowly, I think, and there is still the problem of the gravity providing power by moving the masses. With your mechanical rectifier, the downward rocking part has to provide 27 horsepower plus losses, so that your system of gearing can speed that up and provide the torque x rpm to drive the generator.
It might be simpler and more reliable and even more efficient to use the rocking of the Zeds to drive the generator by your mechanical rectifier system... but the catch is still the same as with the hydro motor: the input power to the system driving the generator has to be "after" the Zed advantage is applied, and must be at least 27 horsepower, more like 40, to drive the generator.
And if the only source of power back of your rectifier system is the rocking of the Zeds, moving water, and using gravity.... you still need the equivalent of a 10-meter high waterfall flowing at 6 gallons per second or so (not 58 this time), then somehow apply the 960 percent advantage to get from 3 hp to 27 hp to feed your rectifiers..... or even stranger, following Mister Wayne's description, you need 30 hp coming from or inside the Zeds, to be able to take one part, 3 hp, to run the system and return 9 times that NET to the consumer, 27 hp, to drive the 20 kW generator.