Claim: Free Energy - 1000 Times Overunity

[MasterPlaster]

Begginers should start here:

http://en.wikipedia.org/wiki/Irving_Langmuir

[Goat]

Hi All

Very interesting post @Meta but after looking at some links to Atomic Hydrogen Welding at http://www.specialwelds.com/underwater-welding/atomic-hydrogen-welding.htm one thing struck me that was not included in the calculations, if it was I may have missed it and that is the input to create the plasma arc between the 2 tungsten electrodes.  According to the link above the input to produce the arc is in the order of a few Kilo Watts..."The power source is a transformer that has an open circuit voltage (OCV) of up to 300 volts to strike the arc, but welding current is low, with generally amperages of 10-20 being used, although this particular AEI model offers a maximum of 50 amps."

Not trying to be discouraging but was this calculated when the author mentioned the following?

The dissociation energy, subtracted from the gross output, would be the net output:

109,000 cal/gram mole (gross heat output) Minus - 103 cal/gram mole (dissociation energy = Unity")

Leaves - 108,897 cal/gram mole (net output - "Over-Unity" because the hydrogen didn't have that much calorific energy in the first place, and was not 'consumed' in the second place)

If I have misread anything please feel free to correct me.

Regards,
Paul

[Cherryman]

Hi All

Very interesting post @Meta but after looking at some links to Atomic Hydrogen Welding at http://www.specialwelds.com/underwater-welding/atomic-hydrogen-welding.htm one thing struck me that was not included in the calculations, if it was I may have missed it and that is the input to create the plasma arc between the 2 tungsten electrodes.  According to the link above the input to produce the arc is in the order of a few Kilo Watts..."The power source is a transformer that has an open circuit voltage (OCV) of up to 300 volts to strike the arc, but welding current is low, with generally amperages of 10-20 being used, although this particular AEI model offers a maximum of 50 amps."

Not trying to be discouraging but was this calculated when the author mentioned the following?

This is a simple diagram of how i get it:



And you only need the water and electrolysis if you somehow loose your hydrogen.



The dissociation energy, subtracted from the gross output, would be the net output:

109,000 cal/gram mole (gross heat output) Minus - 103 cal/gram mole (dissociation energy = Unity")

Leaves - 108,897 cal/gram mole (net output - "Over-Unity" because the hydrogen didn't have that much calorific energy in the first place, and was not 'consumed' in the second place)

If I have misread anything please feel free to correct me.

Regards,
Paul

H Paul,

Notice this paragraph:

The way it works is by simply blowing hydrogen through an electric arc, which dissociates the hydrogen into its atomic state and produces very high temperature, high enough to melt tungsten (melting point 3422 °C, 6192 °F),. Blowing the hydrogen at hot tungsten wire had similar effect,which would be easier to do. The whole article is in the linked pdf file on page 81.

So your question still stand about if this energy is calculated along, but a glowing wire could be less energy as a plasma spark.

I see it someway like this:


And the electrolysis and water are only needed if you somehow run out of hydrogen.

[ramset]

Well
maybe I miss understood ?

When you put a lit HHO flame up against a Tungsten element you get 5000 or so degrees
All the energy it took to do  and sustain that was a match?

What's all this Kilowatt tungsten element stuff?

Chet

[nightlife]

 Wouldn't the heated tungsten wire melt when the hydrogen hits it? If the wire is heated enough to glow and hydrogen is added to create even more heat then the heat of the heated wire, I would think it would melt the wire.