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another small breakthrough on our NERD technology.

Started by Rosemary Ainslie, November 08, 2011, 09:15:50 PM

Previous topic - Next topic

0 Members and 12 Guests are viewing this topic.

picowatt

Rosemary,

Are you talking about the colored horizontal boxes along the bottom of the screen?  The ones that say for example from FIG. 3:

1: 2.00V
DC1M(ohm)
ofs 4.56 volts

2: 100V
DC1M(ohm)
ofs -172

3: 10.0V
DC1M(ohm)
ofs -23V

etc,

PW

Rosemary Ainslie

Quote from: picowatt on April 07, 2012, 10:37:58 PM
Regarding the Q2 bias current.

When the function generator output is a negative voltage, this negative voltage is applied to both the gate of Q1 and the source of Q2.  The negative voltage at the gate of Q1 does nothing with regard to Q1, except keep Q1 turned off.
Which means what?  That there's a positive signal applied to the Gate of Q1?  Shouldn't this allow for a positive flow from the battery supply?

Do you mind if we tackle just this question first?  It's germane to the argument.

Regards,
Rosemary

Rosemary Ainslie

Quote from: picowatt on April 07, 2012, 10:57:53 PM
Rosemary,

Are you talking about the colored horizontal boxes along the bottom of the screen?  The ones that say for example from FIG. 3:

1: 2.00V
DC1M(ohm)
ofs 4.56 volts

2: 100V
DC1M(ohm)
ofs -172

3: 10.0V
DC1M(ohm)
ofs -23V

etc,

PW
Yes

picowatt

Rosemary,

When the FG output is a negative voltage, a negative voltage is applied to the gate of Q1.  This does not turn on Q1, but keeps it in its off state.

Where did I say that during the portion of the FG cycle, when the FG output is a negative voltage, a "positive" voltage is applied to the gate of Q1?  I did not say that.  Obviously Q1 will turn on if its gate is made positive.  But I was discussing the portion of the cycle when the FG output is a negative voltage, and during that period, Q1 is off.

PW

Rosemary Ainslie

Quote from: picowatt on April 07, 2012, 11:05:45 PM
Rosemary,

When the FG output is a negative voltage, a negative voltage is applied to the gate of Q1.  This does not turn on Q1, but keeps it in its off state.

Where did I say that during the portion of the FG cycle, when the FG output is a negative voltage, a "positive" voltage is applied to the gate of Q1?  I did not say that.  Obviously Q1 will turn on if its gate is made positive.  But I was discussing the portion of the cycle when the FG output is a negative voltage, and during that period, Q1 is off.

PW
And so am I.  If the one gate is biased off - then the other is biased on.  I would have thought?

Again,
Rosemary