another small breakthrough on our NERD technology.

[Rosemary Ainslie]

You are applying it incorrectly. You are multiplying noise by nonsense, and you don't even account for the fact that your shunt is 0.25 Ohms, and you think that where the scope says "V V" it is saying "W". But it's not.

WHERE HAVE I EVER SAID THAT THE MATH TRACE IS SHOWING A WATTAGE?  Your over reliance on this piece of misinformation is tedious - IN THE EXTREME.  IF there was ever any confusion it was NOT of my making but of your own.  I have NEVER been guilty of saying, implying or assuming that the math trace was doing anything more nor less than giving a product of the voltages.  IT IS USED AS A GUIDE ONLY.  When we get that negative product then - WE WILL ALSO, INEVITABLY AND OBVIOUSLY AND LOGICALLY - GET A NEGATIVE WATTAGE. 

Rosie Pose

[TinselKoala]

Indeed.  So do I.
Rosie Pose

Things move fast, Rosemary, and you are falling behind.

Don't you have some kind of TEST to be getting ready for?

[TinselKoala]

Rosemary, do you see that "deskew" setting on the right of those shots that you posted and fuzzy just linked to? The setting that's set exactly to zero?

Do you know what probe skew is and what it can do to power measurements?

NO, in spite of several people and several documents telling you about it, you still refuse to learn.

[Magluvin]

Things move fast, Rosemary, and you are falling behind.

Don't you have some kind of TEST to be getting ready for?

Well, thats what I thought the reopening of this thread was all about. "RosePoynt"  But look what it has turned into. Just like it was before the thread was locked.

Mags

[TinselKoala]

WHERE HAVE I EVER SAID THAT THE MATH TRACE IS SHOWING A WATTAGE?  Your over reliance on this piece of misinformation is tedious - IN THE EXTREME.  IF there was ever any confusion it was NOT of my making but of your own.  I have NEVER been guilty of saying, implying or assuming that the math trace was doing anything more nor less than giving a product of the voltages.  IT IS USED AS A GUIDE ONLY.  When we get that negative product then - WE WILL ALSO, INEVITABLY AND OBVIOUSLY AND LOGICALLY - GET A NEGATIVE WATTAGE. 

Rosie Pose

In the video that you now disavow and repudiate... the presenter says, with your prompting, "five or  or six watts" and he's gesturing... and you are reading.... the multiplication numbers in the parameters box, where it says VV not W. And of course since you do not take into account the fact that your CVR is 0.25 ohms... you treat it as if it were one ohm and just ignore it. To get an instantaneous power trace, you need to divide the VOLTAGE DROP across the CVR by the resistance. I = V/R, remember? THEN you may multiply that by a correctly obtained and RELEVANT voltage trace. "Correctly obtained" means accounting for stray lead inductance AND PROBE SKEW which you have not done. In other words, you are multiplying garbage by noise and getting nonsense as a result.

TEST YOUR BATTERIES in any of the many ways that have been discussed here. SHOW YOUR WORK. Show that you have some minimal understanding of the circuit and how to make power measurements properly.

Or is something keeping you from PROVING ME WRONG? Wouldn't it be satisfying to you, to at least refute ONE thing?

Have you had somebody with eyesight explain that JT video to you yet? Because once again what you assert is simply incorrect.