Testing the TK Tar Baby

[TinselKoala]

TK,

If your shunt is truly 1.75uH, it would be closer to 16 ohms at 1.5MHz.

PW 

Yes, that's right. And there is no indication that Rosemary used any other type of resistor than the simple wirewound "cement" power resistors that are shown in the video and are listed in her bill of materials. Therefore, her very low inductance value is likely to be in error, and nowhere in any of her data is it evident that she did anything other than a direct multiplication of the voltage drop across the resistor with the battery voltage.

However, it makes no difference in the SIGN of the current through the resistor, just the magnitude, right? And the sign of the power is determined by the sign of the current, since the battery voltage is always positive, isn't it?

[Rosemary Ainslie]

Rosemary,

I for one wish you would "lighten up".  It seems you never "discuss", you always just want to "argue".

It's not very pleasant nor professional.

PW

My dear picowatt

If I ever needed any evidence of 'partiality' it's in this post of yours.  I most certainly HAVE NOT BEEN either unpleasant or unprofessional.  I think the most lenient of accusations would be to say that it is TK who has been excessively combative and entirely unprofessional.  ANd I'm NOT even confining this comment to his work.  And it is HE who has required that I don't engage.  So. PLEASE.  Exercise a modicum of reasonableness in your opinions related to this.  It's GLARINGLY inappropriate.

Regards
Rosemary

[Rosemary Ainslie]

Yes, that's right. And there is no indication that Rosemary used any other type of resistor than the simple wirewound "cement" power resistors that are shown in the video and are listed in her bill of materials. Therefore, her very low inductance value is likely to be in error, and nowhere in any of her data is it evident that she did anything other than a direct multiplication of the voltage drop across the resistor with the battery voltage.

However, it makes no difference in the SIGN of the current through the resistor, just the magnitude, right? And the sign of the power is determined by the sign of the current, since the battery voltage is always positive, isn't it?

Actually no.  It's still not right.  But perhaps Poynty will enlighten you both.  In due course.  And far be it from me to capitalise on an error.  Unlike you TK I would not charge through 20 pages referring to it ad nauseum in the hopes of thereby denying any competence to any of you.  It's not my style.  And nor do I need to.  Your own lack of it is everywhere apparent.  Fortunately there are those readers here who are well aware of it.

Rosie Pose.

[Rosemary Ainslie]

However, it makes no difference in the SIGN of the current through the resistor, just the magnitude, right? And the sign of the power is determined by the sign of the current, since the battery voltage is always positive, isn't it?

And here's another error.  We have examples where the battery indicates a negative voltage.  Go figger!

Again,
Rosie Pose

[TinselKoala]

OK... so here's a "correction" if indeed it is a correction. Note that the shape of the graph and the sign of the average power does not change, only the magnitude of the power level changes.

Any other problems?