Testing the TK Tar Baby

[Rosemary Ainslie]

Look.

I travel at 10 miles per hour for half an hour.
Then I speed up and travel at 20 miles per hour for another half an hour.

How far did I go in that hour? What was my AVERAGE SPEED? What was my speed at the 15 minute mark?

I went (10 miles/hour) x ( 1/2 hour) = 5 miles. Note that the units cancel and are correct.
I also went (20 miles/hour) x (1/2 hour) = 10 miles. Note that the units cancel and are correct.

Adding these, I get 15 miles travelled, in one hour. Taking one hour as the interval and 15 miles travelled, I AVERAGED 15 miles PER hour. But my speed at the 15 minute mark was 10 miles per hour.

This is the difference between an INSTANTANEOUS RATE and an AVERAGE RATE, Ainslie.

A Watt is like a Mile Per Hour. A Joule is like a Mile.  A mile is NOT the same thing as a mile per hour, and is NOT the same thing as an hour per mile.


And this, by the way, is what is meant by "SHOWING" a computational result. I SHOW the numbers, the units, the operations, the results and the interpretation. All you do is waggle your gums.

I don't give a tuppeny damn if you traveled at the speed of light for 1 second and then stayed static for 20 years thereafter.  Your ACTUAL speed - the actual energy that you expended would be factored over 20 years.  Any attempt to claim a velocity at the speed of light would be erroneous. 

R

[TinselKoala]

So what. Define it however screwy way you like, you are still wrong, and you have AGREED that you are wrong in your blog statement, since 320 mA is not negligible at all.
Therefore the conclusion that you came to is also wrong, just like your bogus attempt at redefining power measurements.

And yes, I will continue to point out your lies and errors whenever they occur, WITH REFERENCES, as long as you maintain them.

Read the first paragraph in your blog post and then reconcile that with your admission that 320 mA is flowing during the ON time.

[picowatt]

AGAIN.  You are trying to IMPLY that watts can be separated from POWER.  IF you are trying to determine the amount of energy dissipated at the load resistor then you are REFERENCING A POWER MEASUREMENT.  This is ALWAYS BASED ON WATTS and those WATTS NEED TO BE DETERMINED OVER TIME.  AGAIN.  Here's that equation.

Rosie Pose

Again, what's the beef?

Pavg is as you are stating, but the number you need to plug in for that "W" is 20 watts.

Heck, I thought it was a win win.  But now that I see that you consider this amount of power draw from the battery (instantaneous or average) insignificant or miniscule, that would be somewhat subjective.

Keep in ming that this is only the dissipation during the positive portion of the FG cycle.  When the FG output swings negative, applying a negative voltage to the source of Q2, Q2 is biased on and bias current flows thru the FG.  The Q2 bias current must therefore also be factored in to arrive at the total dissipation over the full cycle.  The amount of bias current flowing in Q2 need either be measured directly or estimated from the FG open circuit voltage, Rgen, and the Q2 threshold characteristics.

PW

[TinselKoala]

I don't give a tuppeny damn if you traveled at the speed of light for 1 second and then stayed static for 20 years thereafter.  Your ACTUAL speed - the actual energy that you expended would be factored over 20 years.  Any attempt to claim a velocity at the speed of light would be erroneous. 

R

You really don't get it. You are sad, sad sad.

Let's do it again. If I travel NOT AT LIGHT SPEED but at 10 miles per hour, and NOT FOR ONE SECOND, but for half an hour, HOW FAR (not how fast) HAVE I GONE?

And if I then travel at 20 miles per hour (NOT STANDING STILL) for half an hour (NOT 20 years) HOW FAR HAVE I TRAVELLED? (Not how fast.)

How far have I gone in total? How long did it take? What is my average speed, and finally.... WHAT WAS MY SPEED AT THE 15 minute mark?

[TinselKoala]

@PW:
The duty cycle, as far as I can tell from measuring the traces, is about 12.8 percent ON.  The only way to get to the 3.33 Watt average figure from the electrical parameters is to use some estimate of the current during the OFF time as well as the roughly 2.5 Watts average computed from the ON time duty cycle alone.
But who knows where that 3.33 figure came from. She won't tell us, or rather, she refuses to SHOW us how it was obtained.