Testing the TK Tar Baby

[Rosemary Ainslie]

picowatt - here's your statement.

When the Fg output is a negative voltage,  the negative voltage applied to the gate of Q1 turns Q1 off.  Simultaneously, a negative voltage is applied to the source of Q2 (the source of Q2 and gate of Q1 are connected and therefore always the same voltage).

You claim a negative signal at the gate of Q1.  You claim a simultaneous negative to the Source of Q1.  You admit to a connection between the source of Q2 and the Gate of Q1.   You OMIT reference to the connection between the source and gate of Q2.  IF the Source of Q2 is NEGATIVE - then the GATE OF Q2 is ALSO NEGATIVE.  Therefore - you are claiming that switch at Q2 is ON ... NOTWITHSTANDING A NEGATIVE SIGNAL AT THAT GATE.

Now.  I'm missing a very interesting program.  Cheers guys.

Rosie

[derricka]

Rosemary scared? Nah. Rosemary isn't scared about being wrong. If she was, she would have given up years ago. Make no mistake though, she isn't fooling anyone with a solid background in electronics, and good measurement skills. Her latest conflation of MOSFET source and drain is no exception.

[fuzzytomcat]

..... snip rubbish .....

Now.  I'm missing a very interesting program.  Cheers guys.

Rosie

I see this one is on your "FAVORITES" list Rosemary ..... http://www.youtube.com/watch?v=PKhf8tXJqRM .....

[TinselKoala]

picowatt - here's your statement.

When the Fg output is a negative voltage,  the negative voltage applied to the gate of Q1 turns Q1 off.  Simultaneously, a negative voltage is applied to the source of Q2 (the source of Q2 and gate of Q1 are connected and therefore always the same voltage).

You claim a negative signal at the gate of Q1.  You claim a simultaneous negative to the Source of Q1.  You admit to a connection between the source of Q2 and the Gate of Q1.   You OMIT reference to the connection between the source and gate of Q2.  IF the Source of Q2 is NEGATIVE - then the GATE OF Q2 is ALSO NEGATIVE.  Therefore - you are claiming that switch at Q2 is ON ... NOTWITHSTANDING A NEGATIVE SIGNAL AT THAT GATE.

Now.  I'm missing a very interesting program.  Cheers guys.

Rosie

Sic.

You idiot Rosemary. Look at YOUR circuit diagram. THE SOURCE OF Q2 AND THE GATE OF Q2 ARE NOT CONNECTED. Except of course through the function generator. Now, since the FG puts one polarity at one wire and the other polarity at the other wire...Well, DO THE MATH.

Of course if you are using a DIFFERENT schematic.... why don't you reveal it? It would explain much that is currently unexplained. Pun intended.

[Magluvin]

I have understood this before Rose began trashing me. It is very easy to understand that if the source of the mosfet has negative potential put to it, in reference to the gate polarity, the mosfet will turn on. It isnt hard to understand once we understand the difference in potentials happening between the gate and source at the time.

Even if the gate has a negative potential, in which one might say the transistor should be off at the time, if the source is more negative, the transistor will turn on. Because the gate is positive in reference to the sources more negative polarity.

It is pretty simple.

Mags