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quentron.com

Started by Philip Hardcastle, April 04, 2012, 05:00:30 AM

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profitis

Sarkeizen:'Don't pop any more vitamins.  They seem to make you less smart. :)'

If it takes being dumb to get you into such easy corners give me more :)

sarkeizen

Quote from: profitis on April 24, 2015, 03:44:08 PM
How can a theorem restrict a machines performance
The BBBV restricts the ability to create a machine using quantum effects which has a complexity class of O(1) (for sorting) because the BBBV states that the greatest improvement you can get from quantum effects is O(X^1/2).

Quoteand at the same time insist that you meant the above in a different context
Please rephrase in English.  I don't know what you're referring to as "a different context".

I'll just point out than in this current exchange I've asked you three or four questions concerning the questions you are asking and you can't answer them.  Isn't that kind of cool.  That you don't even know what you're talking about enough to answer a question like: "What do you mean by algorithm proof?".  Seriously your grasp of what you know is that shitty. :)

sarkeizen

Quote from: profitis on April 24, 2015, 03:49:26 PM
If it takes being dumb to get you into such easy corners give me more :)
ROFL!

If I was cornered it would be trivial to produce a proof that I'm incorrect about something.  So far all you do is ask questions that are excessively vague and stupid. 

profitis

Sarkeizen:'The BBBV restricts the ability to create a machine using quantum effects which has a complexity class of O(1) (for sorting)'

Will you allow me to attatch a switch to the quenco If I can show you how a quenco can work without violating this theorem

sarkeizen

Quote from: profitis on April 24, 2015, 04:07:50 PM
Will you allow me to attatch a switch to the quenco
Sure...in a separate thread about Profitis shitty switched quenco - or some other name.  This thread however is about quenco.  Quenco sorts, it appears to sort in O(1).  Hence it can not function by BBBV.

This is no different than someone saying: I've got a device which can deterministically determine if arbitrary program can terminate.