Simple to build isolation transformer that consumes less power than it gives out

[TheCell]

I bought 3 identical trafos at ebay 220V, 28V 3 Amp 85 Watts


disassembled all of them unwound one secondary and rewound it with the
primary of another trafo, so I got a 1:1 Trafo . The rewound coil is
the upper one . Could not get it so perfect . THe DC resistance is around 17 Ohms.
Cannot measure the impedance.


Like Jack said, if the polarity of one coil is wrong Lamp1 if full lit and Lamp2 is dark.
Both Lamps are 220 V 25W Lamps (used in refrigerator )
Lamp1 is on the first picture the left on (that one with the lower intensity)


Wattmeter showed 9,1W
Input Volts 234,7V AC 50 Hz


P calc = Input Volts * I(Lamp1) = 8,2145 W
Now I think it's better not to rely on the value of the wattmeter.
Input Watts calculated from the values of the multimeter.(As the other values)
With a phase delay U->I of 9 Degrees measured by my scope.
Sorry no picture .


cos(9) = 0,98
->
8,2145 W * 0.98 = 8,05021 input watts
______________________
U(Lamp1) = 45,5 V
I(Lamp1) = 35 mA
P(Lamp1) = 1,5925 W
______________________
U(Lamp2) = 93,3 V
I(Lamp2) = 59 mA
P(Lamp2) = 5,5047 W
______________________
Sum POut = 7,0972 W


_____________________________________________
COP = 0,88


What further improvements can be made?
I could wind 2 identical coils with a much thinner wire. (Don't have many options)
But the DC resistance will be around 30 to 50 Ohms . I think that is not
acceptable, because of the heat losses...




Greetings BK




 

[a.king21]

.



Every time someone sees something new to them they tell the world but I have only seen free energy three times in thirty years and I declined to pursue each of those ideas ( none were original with me )

There is free energy for the taking and it has to be somebodies idea. Once you have seen it you will chase every lead to make it practical.

Hi, iflewmyown,
Can you remember the devices you have seen which gave you free energy? Is there any literature available on-line about then?
Cheers.

[Jack Noskills]

I bought 3 identical trafos at ebay 220V, 28V 3 Amp 85 Watts


disassembled all of them unwound one secondary and rewound it with the
primary of another trafo, so I got a 1:1 Trafo . The rewound coil is
the upper one . Could not get it so perfect . THe DC resistance is around 17 Ohms.
Cannot measure the impedance.


Like Jack said, if the polarity of one coil is wrong Lamp1 if full lit and Lamp2 is dark.
Both Lamps are 220 V 25W Lamps (used in refrigerator )
Lamp1 is on the first picture the left on (that one with the lower intensity)


Wattmeter showed 9,1W
Input Volts 234,7V AC 50 Hz


P calc = Input Volts * I(Lamp1) = 8,2145 W
Now I think it's better not to rely on the value of the wattmeter.
Input Watts calculated from the values of the multimeter.(As the other values)
With a phase delay U->I of 9 Degrees measured by my scope.
Sorry no picture .


cos(9) = 0,98
->
8,2145 W * 0.98 = 8,05021 input watts
______________________
U(Lamp1) = 45,5 V
I(Lamp1) = 35 mA
P(Lamp1) = 1,5925 W
______________________
U(Lamp2) = 93,3 V
I(Lamp2) = 59 mA
P(Lamp2) = 5,5047 W
______________________
Sum POut = 7,0972 W


_____________________________________________
COP = 0,88


What further improvements can be made?
I could wind 2 identical coils with a much thinner wire. (Don't have many options)
But the DC resistance will be around 30 to 50 Ohms . I think that is not
acceptable, because of the heat losses...




Greetings BK

Good work !
DC resistance of 17 ohms does not seem to make strong enough coil but the effect is there. I got 165 ohms in the iron trafo, easily over to 10000 turns in it.
But, now I am confused. You got current limiter bulb at less intensity than the load bulb, same effect I have. When there was no load current limiter bulb was not lit, yes ?

In my test the limiter bulb stayed unlit when load was connected, this is explained by stronger coil.
In the two trafo experiment I got the current limiter bulb on the first trafo and same effect was there, no effect on limiter bulb but more light on output side. What is the difference between these two tests ? In my opinion they are identical.

In your test the voltage on lamp 1 is 45 volts, L has 220 volts coming in respect to ground, and N has 175 volts respect to ground, correct ? Should the power in be now 1.59 watts and not 8.05 watts because potential difference between L and N is now 45 volts and not 220 ? You got watt meter on the wall, what does that tell you ?

Better not wind new coil until this effect has been sorted out. You now got the same effect but if it is not OU then making new coil only makes the output glow brighter still while limiter bulb dimms. If this is not OU then case is closed.

What what the idle power with no load connected ?

EDIT:
I don't know if it makes a difference but in my two bulb test I got the limiter bulb just after the load bulb. Maybe you could test if there this changes anything ? Just move the limiter bulb in N line

[TheCell]

<When there was no load current limiter bulb was not lit, yes ? >
With no load (Lamp2) the bulb (Lamp1) was not lit and the power consumption was about 2 Watts.


<In my test the limiter bulb stayed unlit when load was connected, this is explained by stronger coil.>


In my setup the power that the current Limiter bulb (Lamp1) consumes depends on the load (Lamp2).
And I don't understand why Load:Lamp2 lights up stronger then CurrentLimiter:Lamp1 , because both are of the same wattage in my case.




<In your test the voltage on lamp1 is 45 volts, L has 220 volts coming in respect to ground, and N has 175 volts respect to ground, correct ? Should the power in be now 1.59 watts and not 8.05 watts because potential difference between L and N is now 45 volts and not 220 ? You got watt meter on the wall, what does that tell you ?>


The 8,05021 Watts is the power consumed from the wall socket being calculated by the Mains Voltage x I(Lamp1) . The Meter shows 9,1W .


If you have an vfd (variable frequency drive) try minimising input watts.


In the early Thane Heins setup the accelerating under load effect only
occured with high impedance coils and driving the rotor above certain rpms.


I will try high impedance coils, but before purchasing a vfd , I would
wish someone else with this equipment would carry out this experiment.

[Jack Noskills]

Make your test using L - coil - load bulb - limiter bulb - N, with the second coil connected correctly parallel to load bulb.

No need to invest in new hardware yet, you already have the same effect I have. Now it needs to be investigated why those bulbs are not equally bright.

To me this is OU because I had the same effect also with two trafos. Limiter bulb on primary side of first trafo had no light while I got light on load side. Also the coil was warm on the second trafo but cold in the first trafo. When I removed the first trafo and just put limiter bulb effect was the same, but stronger because one trafo was removed.