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Overunity Machines Forum



Simple to build isolation transformer that consumes less power than it gives out

Started by Jack Noskills, July 03, 2012, 08:01:10 AM

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0 Members and 39 Guests are viewing this topic.

TheCell

I moved the current limiting lamp to the other pole ; but nothing seems to have changed.


<Also the coil was warm on the second trafo but cold in the first trafo> [/size]
This is a very valuable hint, because there is no reason for that. The same trafos ; power transfered to the load through 2 of them the temperature of the first should be slightly higher then the second.[/size]

[/size]
Please make 2 measurements with the trafo in idle mode. Connect one of the primaries to mains with a ampmeter in series and let the trafo operate for a few minutes in idle mode. Read the amps and the main volts.[/size]
Disonnect the 2 connectors of the trafo and measure the DC resistance. Whats your mains frequency?
Now I can calculate Inductivity of your primary coil and do a comparision.

Overschuss

Quote from: TheCell on August 20, 2012, 07:41:23 AM
[...] And I don't understand why Load:Lamp2 lights up stronger then CurrentLimiter:Lamp1 , because both are of the same wattage in my case.


Because the current and the voltage are out of Phase (the current lags behind the voltage). Don't forget: The Trafo is an inductive Load. Take a 2-Channel Scope and do a closer look.


Sorry, IMO this is not OU here - but i don't want to discourage anyone here.


TheCell

Because of current laging behind the voltage only does not explain why lamp2 lights up stronger.
But with this circuit will have this effect:
It is not obvious that there is a Capacitance in JNS Circuit , maybe the 2 windings have a capacitance effect.

Jack Noskills

TheCell,

I cannot do this test as I dont have ampmeter, sorry. I have 220V/50 Hz in the grid, so our setups are similar. If you have christmas light trafo that is rated to 20 watts or so you can get the same coils from there. DC resistance of that coil was 165 ohms, so it is much stronger than your coil. I can say that amps are below 20 mA, you could compute impedance according to 5 mA, 10 mA and 20 mA. There is lots of capacitance in the winding as there are lots of turns within 10 mm width.

I looked at your pics when it was running. You measured about 1.5 watts in the first bulb and about 5.5 watts in the second bulb. I dont think 1.5 watts is enough to light up the first bulb to that level. I have tested using 25 watt bulbs also and the lamp dimmly glows even at 5 watts. What I think is that watt meter shows 8 watts that is consumed by the first bulb, what you got in the second bulb is extra and it is more than 8 watts because bulb is brighter.
One way to confirm is that you disconnect the load bulb. There is about 2 watts of idle power in the circuit, so it should be able to light up the first bulb to same brightness. Yet it stays unlit, what is the explanation ?

If you connect and disconnect load, do you see any flickering in the first bulb ? I have noticed that sometimes the first bulb momentarily lights up and then goes out. Could be that 20 ohms coil does not show this effect though.

Lets see how far this reasoning goes:
First you got L - bulb - N, voltage difference between L and N is 220 volts and current flows accordingly, bulb lights up.
Now modify this to get L - bulb - coil - N. Now there is some resistance in the coil, voltage difference between L and left side of coil is now less, lets say it is 180 volts. Current flows still and lamp is less bright.
Next lets get lucky and put a paralle cap across coil so it forms a tank circuit and resonates at 50 Hz. Current stops flowing, voltage difference is now close to zero. As current does not flow then power is not consumed, correct ?
Lets add second coil, L - bulb - coil - coil - N, parallel cap still in place across first coil. Result is still the same, no current flows and no power is consumed, correct ?
Last, put load parallel to second coil, this is the same setup as in the pictures with parallel cap. Now the load lamp will light up, but still no light in the first lamp. Current still cannot flow past the tank circuit and no power is consumed. Situation is still similar as above when looking at the first bulb, correct ?
If this is transformed into two trafo setup where the sniffer bulb is on primary side, effect would be the same. Now, who can explain what is going on with two trafo setup, if not OU ?

If it wasn't for the two trafo setup, I would happily give up at this stage. But damn, I made the two trafo setup first. One trafo setup was continuation to that.

EDIT: added mA estimates

Hope

Relationships between so many projects, which have be proven to have unexplained energy, is where we will find the common factor.   Like the water flowing in pipes then shut down suddenly making the pipes rattle is as I relate this common denominator.   The ends of the "pipes" in this case the being the beginning and end of the circuit.   It sheds light on that saying "split the negative".   


Spark gaps still pass the lines of force even though, at the correct gap per setup, the SG limit other properties.


We are generating and separating the different forces using many methods.  What are the "classes of the forces".  How are each controlled?  If we can apply these specific ideas to the different elements of force (or differences of potential) THEN we WILL know how the extra energy is gained. 


Pressures of all types compress, causes heat, excites the molecules.  An increase in potential.


Relax those pressures and what in turn happens? A decrease in potential.   Decompression, cooling, relaxed and slowed molecules.


At low voltages we generate slow movement of charges, so it takes a lot of these charges to get work done.  The lines of force are minimal.


At high voltages we create focused high speed lines of force.   Not much heat when released do to the decompression (using the force), it will even turn this pressure into work or LOAD.  This will of course cause the charge to lose speed (compression) and suddenly the charge is losing heat (slowing down).


Even the device doing the work will run cold.   


Think about this and when we see it on our own terms and realize these are the facts we will be able to use these principles to design and build working device(s).


High Voltage and high frequency are a double compression method and we can gain a great deal of these different forces ( lines of force) if we decompress both the HV and the HF at the same time.


It will be similar to the forces caused when high pressure, warm air meets with low pressure cool air.


We can find these facts all across the internet easily, but the use of them is for us to realize and build upon them.