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Overunity Machines Forum



Kapanadze Cousin - DALLY FREE ENERGY

Started by 27Bubba, September 18, 2012, 02:17:22 PM

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0 Members and 132 Guests are viewing this topic.

AlienGrey

Quote from: Jeg on February 05, 2018, 01:19:09 AM
Itsu
Thanks for the drawing

Lets suppose that we use a wire of 74m as a secondary and by inserting a top load we make it vibrate again at 1MHz like in the above case. How is that possible at the same frequency of 1 MHz both of the wires (148m &74m) to present max HV at their top sides as a quarter wavelength does?? Isn't that a paradox???

Any physicist here??  ::)
Not really it's easy to see 74 is half of 148 that makes it it's 2nd harmonic, you will get it to tune (sort off) but all you need to do is add 'C' across  the 74 turn winding to tune it you can find a calculator on the web for that, or use a SG and a scope, imagine a kids swing L is the opposite to C you need to balance the act to keep resonance like a clocks pendulum..

itsu

Quote from: Jeg on February 05, 2018, 01:19:09 AM
Itsu
Thanks for the drawing

Lets suppose that we use a wire of 74m as a secondary and by inserting a top load we make it vibrate again at 1MHz like in the above case. How is that possible at the same frequency of 1 MHz both of the wires (148m &74m) to present max HV at their top sides as a quarter wavelength does?? Isn't that a paradox???

Any physicist here??  ::)

Jeg,

i am no physicist, hopefully one will explain, but to my knowledge, the (top)loading is doing that, adding capacitance.

By using (according to the javatc calculator) a 5cm diameter tube, put your 74m / 0.4mm diameter wire in 473 turns around it
and use a sphere topload of 16cm diameter at 2 cm above the tube.

You get this then:


Jeg

Itsu
Thanks again my friend indeed very useful calculations.

But you understand that when we speak about wavelength we speak about exact meters of wire independently of what your top load is. For example someone can tune to a 1MHz frequency using many different wire lengths in combination with many different top load capacities. This doesn't mean that all of the coils are giving out the maximum voltage. Maximum voltage can be given only by the coil which has exactly 1/4 of the total wavelength with the right capacity at the top which helps it to vibrate to the right frequency. Nodes and antinodes have to "step" on the right length over the wire. But as you already said (and confirmed that it is true) relaxation or blocking oscillators will give maximum voltage even if the wavelength corresponds to a zero voltage!!! Isn't that a paradox???

Void

Quote from: Jeg on February 05, 2018, 01:19:09 AM
Itsu
Thanks for the drawing
Lets suppose that we use a wire of 74m as a secondary and by inserting a top load we make it vibrate again at 1MHz like in the above case. How is that possible at the same frequency of 1 MHz both of the wires (148m &74m) to present max HV at their top sides as a quarter wavelength does?? Isn't that a paradox???
Any physicist here??  ::)

Hi Jeg. No, not at all, because the resonant frequency of a coil is dependent on both the coil inductance
and its self capacitance. When you add a top load to a coil, you increase the capacitance seen by the coil,
so it will have a lower resonant frequency. It is the same effect as adding a separate capacitor in parallel
to a coil. That will also lower the resonant frequency of the coil. A coil's resonant frequency is not just dependent
on its wire length. So there are many possible combinations of coil size and a top load or an external parallel capacitor
for a given resonant frequency. The magnitude of the current that flows in the coil as well as the max voltage will
vary for different combinations however. In radio, adding a top load to a vertical antenna raises the current node
in the vertical antenna element somewhat, so this probably also occurs in a coil as well, but probably to a lesser
noticeable extent.

All the best...


Jeg

Hi Void, thanks for the answer. Please see the above post which you have might missed. :)