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Overunity Machines Forum



Kapanadze Cousin - DALLY FREE ENERGY

Started by 27Bubba, September 18, 2012, 02:17:22 PM

Previous topic - Next topic

0 Members and 186 Guests are viewing this topic.

Khwartz

Quote from: verpies on December 08, 2013, 07:34:55 AM
Unless you're dealing with "cold electricity" ;)
lol

QuoteBut seriously now - the calorimetric comparison Wattmeters are indeed accurate but they are not cheap.
I have a HP RF Wattmeter using this calorimetric principle and it costs as much as a good scope!
You don't need such apparatus in a first time, especially for check COPs of > 1.5 in their magnitude, just thermometers! lol

QuoteIt is very slooowww, too :(
Yes, it is, but not so long if you use heating resistors, could take only 1 min to see the difference! :)
QuoteCapacitors do not provide constant voltage to the DUT.
Indeed! but who cares! lol We just want to compare the quantity of energy taken from the supply, here the capacitor, to the energy provided by the output, we do not need in my opinion a constant supply, and any way, voltage batteries are not constant too and low with time... ;)

Khwartz

Quote from: verpies on December 08, 2013, 07:46:40 AM
The kettle method is slow, suitable only for measuring LF and high OUTPUT powers and it suffers from the same problems as outlined in pt.1 - pt.3 of the incandescent bulb analysis. 
Also, it is not suitable for measuring INPUT power because of pt.2
Dry boxes will do, imo.

See you all! i have to go...

Cheers.

verpies

Quote from: Thaelin on December 08, 2013, 05:44:50 AM
How about droping a link to where that sch came from. Seems the cap values are missing.
Attached   ...also read my messages after my post with the schematic, before you assume that it came from elsewhere.

Quote from: Thaelin on December 08, 2013, 05:44:50 AM
Seems the cap values are missing.
All of the capacitors except C5 are filter capacitors, which means: the bigger - the better and the lower their ESR @ HF - the better.

C5 determines the RC time constant of the output integrator formed with R4 and R5.  It averages the output waveform so its frequency is suitable for a voltmeter display (they update their displays less than 10 times per second), so 1μF - 10μF bipolar cap having low-leakage (e.g. like caps designed for S/H applications) would be sufficient.

Grumage

Quote from: verpies on December 07, 2013, 08:21:54 PM
Did you look at the schematic at all?!

All of the power flows through R1, only a small proportion of it is diverted for measurement.
So, the direct answer to your question is: "As much power as R1 can handle".

Dear Verpies and all.

IMO this device, if standardised, would help the vast majority of us that experiment in the realms of OU. If you have studied a number of the videos that Magpwr has uploaded he uses a simple version of what dear Verpies is proposing.


However the CSr might be it's Achilles heel ?? It has got to be able to withstand the current flow, so depending on the voltage applied it might be asked to handle several hundred watts !!
But I feel that the problem is not insurmountable as long as the design parameters are worked with. In other words, don't ask more of the device than what it is capable of doing !! :)

I will be contacting my friend tomorrow and see if he is interested in persuing a working unit.

Cheers Grum.

verpies

Quote from: Grumage on December 08, 2013, 09:12:06 AM
However the CSR might be it's Achilles heel ?? It has got to be able to withstand the current flow, so depending on the voltage applied it might be asked to handle several hundred watts !!
Actually, for kHz frequencies, linear Hall Effect sensors can also be used instead of CSRs.
For a load drawing 10A out of the AC OUT terminals, which at 230V would yield 0-2300W of power transfer, the power dissipated in a 0.1Ω CSR would be 10W.

Note, that the power dissipation in the CSR is independent of the voltage applied to the AC IN terminals, it depends only on the current drawn from the AC OUT terminals, because PCSR=I2RCSR only.