Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

[marathonman]

Correct me if i am wrong but according to my calculations at 18 awg wire in which i am using for my Primaries, it is 6.385 ohms per 1000 ft of wire which is a lot of wire. even at that absurd length 7 Primaries is only 44.695 ohms and at 100 volts 100 ohms i will get 1 amp so i will have to adjust the ohmage accordingly. this doesn't seem to difficult to me or am i missing something. all i have to do is adjust the ohmage to achieve my desired amperage through 9 resistor taps down to .1 amps on the low side, 1 amp for high side. hummmm! does't seem to difficult to me.

Doug;
"none of the inducer magnets going into a non magnetic state or a reverse state"

The whole idea of Figueras splitting up the primaries are to not have to be in a zero magnetic or reverse state. it takes a whole lot more power to reverse the domains of the iron core. by reversing the poles of the electromagnets one N/S and one S/N he didn't have to worry about Hysteresis in the Primaries at all.

[NRamaswami]

Marathonman:

1000 feet is not a lot of wire.. I'm already using 5000 feet of wire.. Yes.. You are right the impedance of the coil is the key.

Doug:

See the current flows from NP1->NP2--->NP7 ---SP7-->SP6-- ---SP1

There are 14 primaries.. It is not necessary for the primaries to lose magnetism..Who knows what is 1/50th of a second..The idea is that the opposite side magnets must become stronger and weaker. If NP is stronger SP is weaker and When SP becomes stronger NP becomes weaker..This creates a state where the magnetic flux is forced to flow in to the secondary.

I have already reached the 200 watts level. Magnetism is increased and remains constant..It needs to oscillate.. That is what the commutator and resistor circuit does..So at very low power input, we have high magnetic flux in the system which makes the secondary get high power output..

I have experienced this when I used high power 200 volts and 7 amps and just two primaries..There are certain things that I'm not disclosing fully here yet but when we have a high electric field and magnetic field combination the secondary is able to produce an excellent output. Figuera has done the same thing at low power input..For a low power input can be easily supplied from the output..Of course secondary will oppose the primary and so we can put a variac to be powered by the secondary output and then use that to provide a fixed input to the system..It becomes part of the output..

Unfortunately I ended up having too much of volts.. And we hit it when we did not have any turns calculations. And we are doing all these things again..

Now for a teaser let me know what will be the output in the transformer below.

Teaser:

I wind 100 turns of insulated wire on a iron pipe within which I put a lot of iron rods. This is the secondary.

Outside of the insulated wire I put another lot of iron rods and then wind the primary insulated wire for 100 turns..

Both the primary and secondary are same guage insulated wires.

The primary input is 220 volts and 7 amps What will be the output of the secondary?

This is a practical hands on experience, first hand experience knowledge and let me see if you can calculate and tell me the answer. I'm sure most will fail this test..Any one can take this test..

[Cadman]

Nramaswami,

The Buforn patent shows the commutator jumpers at the upper left corner of the drawing, as you noted. Just overlay that commutator drawing onto the one with the resistor wire connections and you will see that when jumpered as indicated, and the resistor wires are connected where indicated, that as the brush traverses the commutator there will always be an electrical connection from the brush to a resistor wire. The brush specified (always in contact with two commutator bars) will contact at least two resistor wires at all times, except when the brush is over bars 4 – 5, and 12 – 13. At those points only one resistor wire will be connected. These are the two points of increased 'dwell' I wrote about earlier. For clarity I refer to commutator bar #1 as the bar at the one o'clock position, which is connected to the fifth resistor wire from the left.

@All,
I keep telling everyone that there is nothing hidden in the Buforn patent but it seems few are listening. The only mystery to solve is the correct combination of core size, coil construction, number of coil sets, excitation current, and frequency (commutator rotation speed).

We may discover some unique properties of this generator after it is built. But first it has to be built according to the patent.

[Cadman]

This is what I am building

[marathonman]

I plan on going with everything in the patent but i can't swallow the inefficient commutator.  i think he used it because solid state wasn't present and since there is no spark involved i see no reason to use it. i can do the same with solid state and with way less power than the motor takes to rotate the commutator plus no parts to wear out  and easier to implement.

the picture of Figueras device clearly shows that the Primaries are larger than the Secondaries in which i am making my Primary core 4 times the square of the Secondaries so the only concern i have with that is to not saturate the secondaries as this will mangle the output. i will be doing test in the next week to see just how much flux the primaries will put out and then calculate the ball park figure as to the saturation level of the Secondaries and adjust accordingly. this is one thing i haven't heard any one talk about.

ps. i just redesigned my timing board to accommodate switching transistors MJH11022 TO-247 package. ran through a vitreous wound resistor network ie... 9 resistor taps

HAPPY FIGUERING