Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

Fernandez · July 04, 2015, 10:07:25 PM

Quote(a) is the field between two magnets, (b) the field due to a current in a straight wire and (c) the resulting field if they are put together. This last field is known as the "catapult" field because it tends to catapult the wire out of the field in the direction shown by the arrow.

If we remove the wire in (b) and pass a current through the core do we get the same motor effect? This is just an idea for those still looking for a basic starting point.

Doug1 · July 05, 2015, 07:56:34 AM

Patent 30378 date 1902
In the arrangement of the excitatory magnets and the induced, our generator
has some analogy with dynamos, but completely differs from them in that, not
requiring the use of motive power, is not a transforming apparatus. As much as
we take, as a starting point, the fundamental principle that supports the
construction of the Ruhmkorff induction coil, our generator is not a cluster of
these coils which differs completely. It has the advantage that the soft iron core
can be constructed with complete indifference of the induced circuit, (allowing
the core) to be a (real group) of electromagnets, like the exciters, and covered
with a proper wire in order that these electromagnets may develop the biggest
attractive force possible, without worrying at all about the conditions that the
induced wire must have for the voltage and amperage that is desired. In the
winding of this induced wire, within the magnetic fields, are followed the
requirements and practices known today in the construction of dynamos, and
we refrain from going into further detail, believing it unnecessary.

From Wiki

Magnetic field created by a current The magnetic field created by an electromagnet is proportional to both the number of turns in the winding, N, and the current in the wire, I, hence this product, NI, in ampere-turns, is given the name magnetomotive force. For an electromagnet with a single magnetic circuit, of which length L_core of the magnetic field path is in the core material and length L_gap is in air gaps, Ampere's Law reduces to:^[17]^[2]^[18]
$NI = H_{\mathrm{core}} L_{\mathrm{core}} + H_{\mathrm{gap}} L_{\mathrm{gap}}\,$ $NI = B \left(\frac{L_{\mathrm{core}}}{\mu} + \frac{L_{\mathrm{gap}}}{\mu_0} \right) \qquad \qquad \qquad \qquad (1) \,$ where $\mu = B/H\,$ is the magnetic permeability of the core material at the particular B field used. $\mu_0 = 4 \pi (10^{-7}) \ \mathrm{N} \cdot \mathrm{A}^{-2}$ is the permeability of free space (or air); note that $\mathrm{A}$ in this definition is amperes. This is a nonlinear equation, because the permeability of the core, μ, varies with the magnetic field B. For an exact solution, the value of μ at the B value used must be obtained from the core material hysteresis curve.^[2] If B is unknown, the equation must be solved by numerical methods. However, if the magnetomotive force is well above saturation, so the core material is in saturation, the magnetic field will be approximately the saturation value B_sat for the material, and won't vary much with changes in NI. For a closed magnetic circuit (no air gap) most core materials saturate at a magnetomotive force of roughly 800 ampere-turns per meter of flux path.
For most core materials, $\mu_r = \mu / \mu_0 \approx 2000 - 6000\,$ .^[18] So in equation (1) above, the second term dominates. Therefore, in magnetic circuits with an air gap, the strength of the magnetic field B depends strongly on the length of the air gap, and the length of the flux path in the core doesn't matter much.
Force exerted by magnetic field The force exerted by an electromagnet on a section of core material is:
$F = \frac{B^2 A}{2 \mu_0} \qquad \qquad \qquad \qquad \qquad \qquad (2) \,$ The 1.6 T limit on the field^[14]^[16] mentioned above sets a limit on the maximum force per unit core area, or pressure, an iron-core electromagnet can exert; roughly:
$\frac{F}{A} = \frac {B_{sat}^2}{2 \mu_0} \approx 1000\ \mathrm{kPa} = 10^6 \mathrm{N/m^2} = 145\ \mathrm{lbf} \cdot \mathrm{in}^{-2}\,$ In more intuitive units it's useful to remember that at 1T the magnetic pressure is approximately 4 atmospheres, or kg/cm².
Given a core geometry, the B field needed for a given force can be calculated from (2); if it comes out to much more than 1.6 T, a larger core must be used.

Doug1 · July 05, 2015, 08:34:59 AM

From Tompson and Sulvanius
In the next of Silliamans Journal (Aprill 1831)
Proffesor Henrey "gave an account of a large electromagnet made for Yale College"
The core of the magnet weighed 59 1/2 lbs, it was forged under Henry's own direction
and wound by Dr Ten Eyck. The magnet wound with 26 strands of copper bell wire of total
length 726 ft and exited by 2 cells which exposed nearly 4 7/9 square feet of surface,
readily supported on it's armature, which weighed 23 lbs ,a load of 2063 lbs.

If this is the work done in the 1800's you need to step up your game.

NRamaswami · July 06, 2015, 12:58:42 AM

Doug:

Great work. I hope that with this theoretical background other learned freiends will see the reality. Not knowing any one of this, When I learnt to built electromagnets I wanted to build a powerful electromagnet and so wound a trifilar 300 meter wire (3x100 meters) and wound it on a 4 inch dia and 18 inch long solenoid. The coil drew about 18 amps from the mains and the iron oscillated so vigorously and jerked and the vertical solenoid fell down. The trifilar coil is the 3 core cable that is used for AC wiring and must weigh about 15 to 20 kgm I guess. Iron must weigh at least 50 kgm for that solenoid. I have not measured. When the coil fell down the circuit tripper at office rated at 32 amps tripped. I then realized that this is too powerful and then came to read about saturation. To avoid saturation add more mass of iron was the advice some place. So I want on to add and built a quadfilar coil to reduce the amperage drawn and to make a silent and soft eletromagnet that remained stable and not hot, it required me finally to do it on a 24 inch dia and 18 inch tall plastic tube filled with iron rods as an electromagnet. That was humming and stable. I did not have all the information you have provided and had gone by common sense and observation. I then learnt that if we put secondary wires under the primary the solenoid can be brought down for the resistance of the secondary make the solenoid stable but then it becomes a transformer. If we shunt the secondary the same violent reaction will come. Actually we were fortunate that we were not standing near that coil when it fell down..That was two years back..

@Alvaro_CS.. Your drawing is not correct. The middle coil is half the length and half the diameter of the two primaries. You also show the two primaries as a single coil they are two separate quadfilar coils that we used. I'm not good at drawing on computers. If you can wait for a 10 days I can post a photograph.

Doug1 · July 06, 2015, 08:22:58 AM

NRamaswami

Think back to my prior comments regarding magnetic amplifiers. It is a method to use an extra winding to control the current.Like a regulator or a variac . You did not need to rebuild your first coils by adding more iron you just needed to get control over the source (mains). With a little practice you can use it as an additive source of current to increase flux if you need to in bi stable forward mode. They just amount to slightly different ways to wind an extra coil over the primary sometimes the secondary as well. I have a doc I scrounged from Texas Instruments which covers the use of gaps in a core and shunts outside the windings of a core to cure stray magnetic leakage that produces unwanted EMR on neighboring conductors or components even in the high frequency range. Gaps are a complicated thing.
As far as your first cores ,the ones you rebuilt. The less power you use to operate the better wouldnt you think?

Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

Fernandez

Doug1

Doug1

NRamaswami

Doug1