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Overunity Machines Forum



Re-Inventing The Wheel-Part1-Clemente_Figuera-THE INFINITE ENERGY MACHINE

Started by bajac, October 07, 2012, 06:21:28 PM

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0 Members and 8 Guests are viewing this topic.

NRamaswami

To put it more specifically my doubt is this..

If you make a coil of wire is made to jump, it does nothing.

If you make a permanent magnet move up and down it does nothing,

If you rotate the magnet in empty space do we see any rotating magnteic field. No so the magnetic rays are invisible.

Now when these invisible rays cut the coils made up of conducting materials current is produced in the conducting materials. The argument is that mechanical energy is converted to electrical energy. if that be so if we just make the coil jump and down in the absence of a magnetic field or rotating or time varying magnetic field, current is not produced. We need the combination of rotating permanent magnet and the coil of conducter to generate electricity.

Since in the absence of magnet the mechanical energy is not converted to electrical energy, there ought to be some thing that is present int the magnetic field.. That some thing is certainly not mechanical energy. So a rotating magnet or rotating magnetic field does some thing else to generate current in the coils of wire.

I agree that the current generated in the coils tends to repel the movement of the rotating magnetic field. I also agree that therefore we normally need to give more energy to the rotating of magnet to continue or mainfest the rotating magnetic field. So excess energy is needed to rotate the magnetic field ( not to produce current but to sustain the rotating magnetic field overcoming the force of opposition from the induced current)/

The question is where is this induced current coming from? It certainly is not from the rotating magnetic field as the rotating magnet does not create electricity unless the conductor is placed near it and coiled. Then what happens to the conductor and why the conductor creates electricity.. This is a fundamental doubt..That is not answered in boooks.

I request Farmhand to answer this queston to enable this dummy to understand the situation.. Pleae do not quote from a book but please do give an insightful answer like Gyula gives. I remain very grateful and obliged.

Cadman

Marathonman,

Yes that is the coil and core layout, right from the Buforn patents. The actual gap between my coils is about .050", due to the ends of the coil spools. I notice your drawing does not have the core inserted into primaries at 45% depth, and this is one of the variables I want to experiment with. That 45% was just a guess for a first try.

My build was an effort to verify the patent, as-is. Even though I am convinced the Buforn patent is straight-forward, there are a variety of physical construction details to work out.

You know, having read through this topic at both forums, I don't recall anyone actually building a device that conforms 100% to the Buforn patent. Not even myself as I did not have the commutator setup. It has been discussed every which way from Sunday, but no faithful replication. :)

Please correct me if I am mistaken.




Cadman

Would someone be kind enough to check these figures for coil amperage draw please?

When wiring multiple coils in parallel, the total resistance is calculated the same as for any resistor wired in parallel, correct? Rtotal = 1/((1/R1)+(1/R2)+(1/R3))

So if one coil is 0.9 ohms, the max current draw from a 12v DC supply would be I=V/R = 12 / 0.9 = 13.33 amps.

Three identical 0.9 ohm coils wired together in parallel would be
1 / ((1/.9)+(1/.9)+(1/.9)) = 1 / (1.111)*3) = 1 / 3.333 = 0.3 ohms
12 / 0.3 = 40 amps

Now if I have 3 sets of 3 parallel wired coils, 9 coils total, these three sets wired together in series, would then be 0.3 * 3 = 0.9 ohms. So then we are back to the same amp draw as one coil, 12 / 0.9 = 13.333 amps?

Three 0.9 ohm coils wired in series would be 0.9 * 3 = 2.7 ohms. 12 / 2.7 = 4.44amps

So we could have either 1 coil or 9 coils wired as above and the amp draw from source would be limited to 13.3 amps, or 3 individual 0.9 ohm coils wired in series at 4.44 amps max?

Is this correct?

Thanks

gyulasun

Hi Cadman.

Yes, I think your calculations and deductions are correct. 

Gyula

marathonman

Hi Cadman.
I have revised the above drawing for you and this is what i came up with. Figueras showed that the primaries are larger then the secondaries so in order to comply with this i came up with this. is  this what you are trying to say.  hope you like it!
ps. i think you might want to use 100 volt @ 1 amp..... just a thought.