Single circuits generate nuclear reactions

[AbbaRue]

@Koen1
Your link to the Neo Magnet experiment on the website was quite interesting,
it answered one of my questions "What direction does magnetism draw electrons?"
I was thinking that the direction of the B field should match the direction electrons are pulled.
If that device could overcome the problem of overheating the Neo it should work.
I was considering mixing silica gel with graphite and placing it in a paper tube.
From your crystal cell experiments do you have an idea what ratio of gel to graphite
I would need, to get about 2 ohms per inch at say 4mm width.
Does heating silica gel cause it to melt?

Based on this formula: J = ?CE? = 1 watt/second
108 J would work out to 108 watts. Now math isn't my strong point.
108W / 37V = 3 A     37V / 3A = 12.3 ohms.
So anything less then 12 ohms zapped by 37 volts should give me the 108 J needed?
Did I miss something? Or does that zap have to last a full second to get the 108 J?
If so then we have to multiply that by the pulse width.

[xee]

@ AbbaRue,
For equation J = ?CE? = 1 watt/second, the voltage is the change in open circuit voltage of the capacitor (before discharge minus after discharge) as measured with high impedance voltmeter. Equation is meaningless when the capacitor is connected to a low resistance load or a voltage source while measuring the voltage. When correctly measured, time is not relevant, only the change in voltage.

Actually the way the equation is written is confusing. ?CE? = change in Coulombs of charge in the capacitor of C farads. Amps are number of Coulombs flowing in wire per second. Watts = amps squared times load resistance in ohms. So I think the equation J = ?CE? = 1 watt/second is only true for C=1F, E=1V, and load resistance = 1 ohm. No, it even isn't true then. Bad equation.

[AbbaRue]

@Xee
Looks like you are well versed in electronic theory.
If I discharge a 0.16 F cap. at 37V across a resistor for 200 microseconds.
What resistance do I need to get 108J.

[eldarion]

@Xee
Looks like you are well versed in electronic theory.
If I discharge a 0.16 F cap. at 37V across a resistor for 200 microseconds.
What resistance do I need to get 108J.

A capacitor discharges in 5 time constants.  1 time constant = R * C, or rearranged (tau / C) = R, where tau is 40us.  This gives R=0.00025 ohms.

I still haven't heard any rebuttal of my 6Kw problem mentioned above...

Eldarion

[AbbaRue]

@eldarion
I think the answer has been given.
Most of the beta is absorbed by the carbon and transformed into another form of energy.
Some will be EMP, some as heat.
Only a small portion of the beta from near the surface of the rod escapes the rod.
In fact the EMP produced from the beta colliding with the carbon atoms is probably what we want to harness.
This is the purpose of the B field, to align the EMP inside the rod.
Without the B field the EMP would move in random directions and be lost as heat.
The term Colliding used above may not be the right term, it's only used to illustrate the point.
How the beta is transformed into EMP is unknown.

So no rebuttal is required.