Big try at gravity wheel

[Marsing]

@ markE

i don't get your calculation.

- displaced water volume B, why do you calculate upper side  ( 135 mm not 15 mm )
- why displaced water volume is A + B  not A - B.

according to your pict, total of displaced water must less than displaced volume A.

[MarkE]

MarkE,
It is to our mutual benefit that we do no longer engage in communication,  we always appear to miss each others points.
I did not make any CLAIM, neither did I mention anything about support information.

The point was:
The Wayne skeptics have been demanding a video,  giving ZED working knowledge has been refused since it violates the conservation laws.

The reason for Wasif video was:
Here is a video with no other information, no working knowledge.

The conclusion
The Wasif video means less than nothing, because it provides nothing. It has no value without working knowledge.
The contradiction:  Although Wayne's skeptics think it is everything in the ZED case. 

It is immaterial if what was shown in the video is real or not, at this point it is an enigma
I hope you see the point
I do not want to discourage you with your current exploration of Wayne's piston but I hope you also see the point, that Yours & TKs current posts contradict your previous statements.

Red_Sunset

Red_Sunset as to the Wasif video there is no enigma.  It is a terribly bad fake.  There is a whole thread on it where it has been discussed extensively.  If that is your idea of evidence comparable to Wayne's double talk then you have shot yourself in the foot or worse.

Wayne hasn't offered any evidence of surplus energy for any version of ZED, TAZ or any other device proposed by HER.  Neither have you offered any evidence of surplus energy from any buoyancy machine.  The curtain blew away a long time ago revealing that there was never anything there.  You can put on as brave as a face as you want.  A brave face is no substitute for evidence.

[Marsing]

webby, did i miss the point ?.

[MarkE]

@ markE

i don't get your calculation.

- displaced water volume B, why do you calculate upper side  ( 135 mm not 15 mm )
- why displaced water volume is A + B  not A - B.

according to your pict, total of displaced water must less than displaced volume A.

Marsing,  There are two places where "air" can displace water:  Volume A which is the cavity formed between the inverted cylinder and the top of the piston, and Volume B in the annular gap between the piston OD and the inverted cylinder ID.

I let the pump run until both cavities fill with "air".  Therefore the displaced water is the sum of the cavity volumes:  A+B.

Initially, the volume of the annular cavity is: (15mm^2 - 14.23mm^2) * pi/4 * 150mm ( full height of the piston ).
As we fill the cylinder rises 15mm, we can either calculate the cavity volume projected directly above the piston:  14.23mm^2 * pi/4 * 15mm as the added displacement, or we can get the same total result by taking the entire 15mm diameter "bubble" volume above the piston top surface and then calculate the annular cavity around the piston proper as now 135mm long.

So, using one method we get:

Annular ring:  (15mm^2 - 14.23mm^2) * pi/4 * 150mm
Bubble projected above piston:  14.23mm^2 * pi/4 * 15mm

Or, by the other method:
Annular ring: (15mm^2 - 14.23mm^2) * pi/4 * 135mm +
Entire bubble above piston:  15mm^2 * pi/4 * 15mm

Simple algebra shows that the two quantities are identical.

It is not necessary for both cavities to fill with "air" in order for the cylinder to rise to the stop.  The proposed cylinder composition is massless, volumeless, with an SG of 1.0.  Consequently, it is neutrally buoyant and can move anywhere up or down without an energy cost.  If we assume zero surface tension and friction between the cylinder and the water, then we only have to pump in an infinitesimal amount of "air" in order for the surrounding water to push that "air" up the annular ring until it encounters the underside of the cylinder top and then transmits the infinitesimal force of the displaced water to the cylinder causing it to accelerate ever so slowly towards the stop. 

[minnie]

   Mark,
          In reply 962 is atmospheric pressure involved?
              Thank you,
                            John.