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Overunity Machines Forum



Big try at gravity wheel

Started by nfeijo, May 03, 2013, 10:03:04 AM

Previous topic - Next topic

0 Members and 25 Guests are viewing this topic.

Marsing

yes,
8 posts are mine ,
2  from mark,
1 from red,
the rest i don't know    >>     ???      <<
 
i made 8 empty posts to jump to this page, as it did not work so i gave up.

TinselKoala

Quote from: webby1 on February 07, 2014, 09:43:06 AM
There is an advantage to being the one who adds the energy, that is you can pick and choose how it is done.

Some times you can take 2 systems that have a given value of efficiency and add them together and raise the efficiency of the system as a whole.

Can you give an example of such a case? Other than Travis's system, I mean.

Generally speaking.... efficiencies "multiply" rather than add. So if you have one system that is, say, 90 percent efficient --say, an electric motor -- and you put the output of that into a system -- say a generator -- with 80 percent efficiency, you get 0.90 x 0.80 = 0.72, or 72 percent efficiency overall.

MarkE

Quote from: webby1 on February 07, 2014, 09:45:45 AM
Strange server behavior.

anyone else not getting some of the posts?

My response gave a new page and MarkE had his response on its own page and it looks like some posts might not be showing up.
I think that the server may have choked on my diagram. I've reduced the resolution this time.
The basic arrangement is that we have the same set up as in the previous drawing, but now we will do work lifting a payload weight.  I choose a payload with a dry weight of 2.22 gms and an SG of 10.0 so that it has a submerged weight of 2.00gms.

We start with the cylinder on top of the piston.
We place the payload on top of the cylinder.
We pump in 2cc of "air" under the cylinder.  The cylinder with the payload on it is now neutrally buoyant.
We pump in an additional 0.1cc of "air".  The cylinder now rises 15mm to the stop.
We remove the payload.  The work extracted is:  2.0gms * 15mm * 9.8m/s/s = 0.294mJ.
We vent the bubble under the piston and by unspecified means recover all of the energy in the bubble.
We push the now neutrally buoyant cylinder back down to the starting position.

Work input:  2.1cc water displaced from 315mm at 9.8m/s/s = 6.48mJ
Work extracted: 0.294mJ + 2.1gms * (165mm + Hbubble/2) * 9.8m/s/s.  Hbubble = 11.9mm.  Work extracted = 0.294mJ + 3.518mJ = 3.81mJ
Cycle energy efficiency = 3.81mJ / 6.48mJ = 58.8%

I chose the 2.22 grams mass so that the "air" injected under the cylinder would cause the cylinder plus payload to become neutrally buoyant before the annular ring filled with "air".  If the payload weight is too heavy the annular ring would fill without the cylinder rising and any additional air would just leak out.  I chose the 2.22 number because the arithmetic is easy with an SG of 10.0: 2.00gms submerged weight.

minnie




   Sunset,


              ruling out stored potential,


       have you ever witnessed a working gravity/buoyancy device?


       If no, has someone you know seen such a device?


       If no to both above, have you documentary evidence to support your claim?


       Yes/no answer acceptable .......honesty a must!


                            John

MarkE

OK it was the diagram that made the server choke.  I've moved a lower resolution image into my response.  All should be good now.