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Overunity Machines Forum



Big try at gravity wheel

Started by nfeijo, May 03, 2013, 10:03:04 AM

Previous topic - Next topic

0 Members and 16 Guests are viewing this topic.

Marsing

Quote from: MarkE on February 09, 2014, 07:44:42 AM
Yes, I can but I do not see any reason to name drawings that represent what Webby is describing after myself.  I think that would be confusing.

yes , it will be confusing,
or  "Webby is describing to markE" .  no bargain

Marsing

Quote from: webby1 on February 09, 2014, 08:05:48 AM

I am not picky either :) ,, but it is not my idea.


i am too, and   yes that not yours,  but that filename was not fair ,  it's seem you are asking for a help with that name.  :)

MarkE

Quote from: webby1 on February 09, 2014, 08:05:48 AM
I am not picky either :) ,, but it is not my idea.

MarkE, the videos did not show a "new" effect and IIRC Tom called the displacement replacement effect the "Travis" effect,, like other kind of things are not treated in a similar fashion. <= sarcasm

Scientists stated, that heavier than air craft can not fly, scientist stated that bumble bees should not fly,, this is all part in expanding our understanding of things, what we thought was this way ends up being that way instead.

This is about how I got myself to my understanding of Wayne Travis's device, that is what I am trying to walk MarkE through, however, his comprehension of my writing and my ability to write in a comprehensible way are at odds.


The payload is the max that A can lift and, as I stated, I find that this makes for an 83 percent efficient lift from the potential that is stored in B.  After A has lifted then A becomes the store for B,, back and forth it goes BUT the transfer pump needs to be changed to make this happen much better.

Since MarkE has a very hard time interpreting what I write this may get even more out there,, but I will try.

If the transfer pump were a pressure balancing system, that is if it could take in a high pressure at a low volume and convert that into a lower pressure higher volume then the process of making that exchange becomes much more efficient.

A simple approach is to think of 3 discs that have a good thickness to them and they are stacked on top of each other making like a pyramid shape, and they move in a housing as such that at first the smallest disc sees the incoming pressure and moves the whole assembly and after a distance of motion that first disc moves away from its seal and exposes the next larger disc, it moves and opens the chamber up to the last disc, this allows for a pressure drop and volume increase and then a volume increase with the pressure drop to match closer to the potential coming from the stored potential in the cylinder.
Webby it would be best to stay on topic and finish defining the arrangement.  At the moment I am waiting for you to define a payload weight and SG.  Surely if you have already been through this you have values that you like.  For the apparatus as it is currently described I can recommend a 2.934g dry weight payload with an SG of 10.0.  That payload will have an underwater weight of 2.641g, 0.01g less than the weight of water that can occupy the annular ring between the piston and the cylinder with the cylinder all the way down as shown for the "A" side at the starting condition you have stated while the  "B" side completely filled with "air" resting up against the stop.  The difference of 0.01g is so that with the "air" displacing all the water in the "A" annular ring we will have a small net buoyant force to lift the payload initially above the piston.  Once the cylinder clears the piston so that there is "air" between the piston and the cylinder underside, then the force will of course initially jump and then decay somewhat as the cylinder moves up and more "air" fills the expanding piston to cylinder underside cavity.  As long as we remain net buoyant, and under these conditions we do, then the cylinder successfully lifts the payload by 15mm, where we can remove the payload and count the work done. 

Our remaining task then is to return the apparatus to the State 2 condition you have stipulated as the cycle starting point where the "A" cylinder is down on the piston once more, there is no "air" on the "A" side and the "B" side is back to holding all the "air" that it can.  Please clarify how you would like to return to that condition:  For instance by pumping "air" from the "A" side back to the "B" side.  Running the transfer pump in reverse works for me.  If you want to vent and use the surface pumps that's fine too.  I just need to know what you have in mind.

Unless there is something particularly important to you about the internal design of the transfer pump, why don't we simply assume that the transfer pump is 100% efficient?

If you share Marsing's objection to the filenames, let me know and I will change the names of new postings to something you like.

MarkE

Quote from: Marsing on February 09, 2014, 08:19:02 AM
i am too, and   yes that not yours,  but that filename was not fair ,  it's seem you are asking for a help with that name.  :)
Marsing I do not understand your concern.  The thought problem that we are working is the one that Webby is defining bit by bit.  If Webby objects to the filenames he can suggest something else.

Marsing

forget about it markE.  you are right,  and thank you     :)