Energy from the Ground - Self powered generator by Barbosa and Leal

[pavqw]

Yes, it could be. I can feel with my fingers there is some charge on the coil even it is unplugged for a while.
I swapped ground from the grid to central heating (it is grounded too) and it works too, input consumption is same - currently around 70uA.

Well, even it is electrostatic energy and you use it in any way, it has to add current in the source.
If not, it is overunity and you can catch as much electricity as you want without affecting a grid - physics law should be broken then.

[nelsonrochaa]

Yes, it could be. I can feel with my fingers there is some charge on the coil even it is unplugged for a while.
I swapped ground from the grid to central heating (it is grounded too) and it works too, input consumption is same - currently around 70uA.

ok 70ua on input it seems like a ambience electrostatic interference .You use a analog or digital meter? .did measure the output ?

[pavqw]

Output consumption is always cca 3uA lower than input, so input is for example 73uA and 70uA output.
It is clearly visible that if I add some load to output consumption on both sides is changing proportionally.
For example I added just LED, then there is 40uA consumption (on both sides nearly equal). Then I throw it away and there is 0.002uA which is 0 + measurement error.
It is digital meter.

[nelsonrochaa]

Output consumption is always cca 3uA lower than input, so input is for example 73uA and 70uA output.
It is clearly visible that if I add some load to output consumption on both sides is changing proportionally.
For example I added just LED, then there is 40uA consumption (on both sides nearly equal). Then I throw it away and there is 0.002uA which is 0 + measurement error.
It is digital meter.

man you cant draw current from the grid because you don't transfer by induction .
If you put a lamp connected to phase and nothing in other side you can consume anything now if you connect the lamp in phase and in ground , then you can measure and will consume.
the circuit don't have direct connection to phase or magnetic coupling .
When i have some time i will make a model for compare my results with yours.
try to make reverse engineer of the circuit.
try measure the circuit without the ground and with the ground . the measure you make are in phase cable or in ground cable ? 

[pavqw]

Thank you very much.

I know there is no connection, there is at least 1mm isolation layer.
Still, if I connect some load then circuit is closed if you consider brass with phase and coil (output wire) is together capacitor.
It is closed because load (for example LED) acts as diode and has its resistance.
Then electrons must pass just 1mm thick shrink tube and because there is always EM emmision (or whatever it is) it passes this layer, but of course in very bad shape.
Voltage drops barely but only 1:(big number) of electrons (or whatever it is) passes this barier - so output power can't be good.
With higher voltage transmission should be much better I guess.

Do you know pencil-like indicator can show you where is main grid in the wall without any connection? It detects voltage even for few cm distance, because there is always some emmision.

I am sure that without ground cable there should'nt be any consumption. I have already tried to start it without ground without success, I'll try to measure it too.
Input consumption was measured in the phase cable.