Recover energy from temperature

[LibreEnergia]

Let me see. Last time I looked,

- Water does not spontaneously flow up hill...
- Gas does not spontaneously compress itself...
- Objects do not spontaneously heat up unless they have a lower temperature than the surroundings
- Heat does not flow from cold to hot.
- Objects at the same temperature are in thermal equilibrium with each other.

All sensible outcomes of the 2nd law of thermodynamics...

Chances of this device working, zero.

[rc4]

Energy won for each volume is :

PSe - PS(e') = PS(e-e')


@LibreEnergia: so, let me know where I'm wrong, this system is not very complex, so it must be easy for you to find where I'm wrong.


Gas is compress/depress with adiabatic process.

[LibreEnergia]

Energy won for each volume is :

PSe - PS(e') = PS(e-e')


@LibreEnergia: so, let me know where I'm wrong, this system is not very complex, so it must be easy for you to find where I'm wrong.


Gas is compress/depress with adiabatic process.

You don't gain energy during the compression. it REQUIRES an external input of work to compress the gas.  Assuming a thermodynamically reversible  system you could recover all that external work input during the expansion phase, the net result however is no net work is done and no energy can be extracted from the system.

[rc4]

Could you explain where I'm wrong in this system ? I would like to learn where I'm wrong.

The energy is more :

PSe - PS(mean e') = PS(e-mean(e'))

Because e decrease more and more when a volume move to the right?

[LibreEnergia]

Could you explain where I'm wrong in this system ? I would like to learn where I'm wrong.

The energy is more :

PSe - PS(mean e') = PS(e-mean(e'))

Because e decrease more and more when a volume move to the right?

What causes the volume to move to the right.?

There must be a pressure gradient for that to occur, correct?
The only way to achieve that is to supply work to the system from an external source, (or alternatively heat from a temperature gradient.)