Mathematical Analysis of an Ideal ZED

[mrwayne]

I am Pretty sure that Larry Shared the hydro assist cost of a dual ZED, and the production...

You might study it a bit more - smile

Just saying... We do not have a steel spring.... or a brick, or a any other false comparison.

Get Back with me after you Study.

Thanks

[MarkE]

I am Pretty sure that Larry Shared the hydro assist cost of a three layer dual ZED, and the production...

You might study it a bit more - smile

Just saying... We do not have a steel spring.... or a brick, or a any other false comparison.

Get Back with me after you Study.

Thanks

The analysis shows without doubt that the "ideal ZED" exhibits the transfer function of a linear spring.  The "ideal ZED" has a force versus distance rate that is constant at 0.48N/mm over its available 2.492mm travel. 

A spring is available on Amazon that is less than 1/1000th the volume of the "ideal ZED", that has the same spring rate and offers more than three times the travel, and can be purchased for ~$1.  If that spring is used only over the 2.492mm of its travel from the fully relaxed position, it does exactly what the "ideal ZED" does between States 2 and 3.

So where is the falsity in the comparison?  What can the "ideal ZED" do that the linear spring cannot, other than:  leak, evaporate, spill over, consume more than 1000 times the space, require a complex and lossy set-up and precharge?

You and your crack team of technologists have free access to the spreadsheet.  You are free to try and poke any holes in it that you might.  It is far more complete than anything I have seen Larry or anyone else from HER/Zydro publish.

[mondrasek]

Good morning, MarkE.  Here is a physical device that could be used to restrain the ZED from rising.  It consists of an "ideal" Massless and Frictionless piston with the same diameter as the riser.  It is fitted into a bore that is also allowed that same "ideal" diameter.  It is below the surface of the bore by a tiny amount less than the ZED is calculated to rise.  The bore is filled with the same quality of water that is used inside the ZED.  This results in a downward Force due to the weight of the water Volume.  That Volume is slightly less than the Volume of the riser lift that is the result of the buoyant Forces in the upward direction once the water charge is introduce in State 2.  So the piston will begin to rise only at the very end of the charge cycle going from State 1 to State 2.  The ZED is now performing real measureable work by lifting the water above the piston as it strokes to State 3.

[mondrasek]

TK, regarding your "peanut oil" comment earlier (sorry, but I'm too lazy to go back and find it).  I was wondering if you, or anyone else, had experience with Pentane?  I did a little bit of research on a low and high density fluid and had settled on Pentane and an Aqueous Sodium Polytungstate solution for candidates to use in a production level ZED system.  Only downside to Pentane though (that I can tell) is it is flammable.  Any thoughts?

http://en.wikipedia.org/wiki/Pentane

http://en.wikipedia.org/wiki/Sodium_metatungstate

[MarkE]

Good morning, MarkE.  Here is a physical device that could be used to restrain the ZED from rising.  It consists of an "ideal" Massless and Frictionless piston with the same diameter as the riser.  It is fitted into a bore that is also allowed that same "ideal" bore.  It is below the surface of the bore by a tiny amount less than the ZED is calculated to rise.  The bore is filled with the same quality of water that is used inside the ZED.  This results in a downward Force due to the weight of the water Volume.  That Volume is slightly less than the Volume of the riser lift that is the result of the buoyant Forces in the upward direction once the water charge is introduce in State 2.  So the piston will begin to rise only at the very end of the charge cycle going from State 1 to State 2.  The ZED is now performing real measureable work by lifting the water above the piston as it strokes to State 3.

This suffers from the tyranny of the:  N*X/N² = X/N problem.
The other problem that you have is that it requires head to support the payload weight.  You have to pick a payload that is less than the initial uplift force, because the uplift force declines steadily towards zero with lift.  If you pick a payload weight that is the same as the uplift force then the thing never moves.  If you pick one slightly less as you propose then it moves only slightly.